1 死锁问题(递归锁,可重入锁)

1 所谓死锁:是指两个或两个以上的进程或线程在执行过程中,因争夺资源而造成的一种互相等待的现象,若无外力作用,它们都将无法推进下去。此时称系统处于死锁状态或系统产生了死锁,这些永远在互相等待的进程称为死锁进程,如下就是死锁
2 可重入锁,递归锁
# from threading import Thread, Lock
# import time
# import random
#
#
# def eat1(lock_1, lock_2, name):
# lock_1.acquire()
# print('%s:拿到了筷子' % name)
# time.sleep(random.random())
# lock_2.acquire()
# print('%s:拿到了面条' % name)
# print('开始吃面')
# time.sleep(random.random())
# lock_2.release()
# print('%s放下了面条' % name)
# lock_1.release()
# print('%s放下了筷子' % name)
#
#
# def eat2(lock_1, lock_2, name):
# lock_2.acquire()
# print('%s:拿到了面条' % name)
# time.sleep(random.random())
# lock_1.acquire()
# print('%s:拿到了筷子' % name)
# print('开始吃面')
# time.sleep(random.random())
# lock_1.release()
# print('%s放下了筷子' % name)
# lock_2.release()
# print('%s放下了面条' % name)
#
#
# if __name__ == '__main__':
# lock_1 = Lock()
# lock_2 = Lock()
# for i in ['张三', '李四', '王五']:
# t = Thread(target=eat1, args=[lock_1, lock_2, i])
# t.start()
# for i in ['赵6', '往7', '傻逼']:
# t = Thread(target=eat2, args=[lock_1, lock_2, i])
# t.start()
### 解决死锁问题 RLock:可重入,可以重复acquire,获得几次,就要释放几次
from threading import Thread, Lock,RLock
import time
import random
def eat1(lock_1, lock_2, name):
lock_1.acquire()
print('%s:拿到了筷子' % name)
time.sleep(random.random())
lock_2.acquire()
print('%s:拿到了面条' % name)
print('开始吃面')
time.sleep(random.random())
lock_2.release()
print('%s放下了面条' % name)
lock_1.release()
print('%s放下了筷子' % name)
def eat2(lock_1, lock_2, name):
lock_2.acquire()
print('%s:拿到了面条' % name)
time.sleep(random.random())
lock_1.acquire()
print('%s:拿到了筷子' % name)
print('开始吃面')
time.sleep(random.random())
lock_1.release()
print('%s放下了筷子' % name)
lock_2.release()
print('%s放下了面条' % name)
if __name__ == '__main__':
lock_1 = RLock()
lock_2 = lock_1
# lock_1 = Lock()
# lock_2 = lock_1
for i in ['张三', '李四', '王五']:
t = Thread(target=eat1, args=[lock_1, lock_2, i])
t.start()
for i in ['赵6', '往7', '傻逼']:
t = Thread(target=eat2, args=[lock_1, lock_2, i])
t.start()