矩阵快速幂

#include<cstdio> 
#include<cstring>
#include<cmath>
#include<ctime>
#include<iostream>
#include<algorithm>
#include<queue>
#include<set>
#define maxint (2147483647)
#define l(a) ((a)<<1)
#define r(a) ((a)<<1|1)
#define b(a) (2<<(a))
#define rep(i,a,b) for(int i=a;i<=(b);i++)
#define clr(a) memset(a,0,sizeof(a))
typedef long long ll;
using namespace std;
int readint(){
    int t=0,f=1;char c=getchar();
    while(!isdigit(c)){
        if(c=='-') f=-1;
        c=getchar();
    }
    while(isdigit(c)){
        t=(t<<3)+(t<<1)+c-'0';
        c=getchar();
    }
    return t*f;
}
ll readll(){
    ll t=0ll,f=1ll;char c=getchar();
    while(!isdigit(c)){
        if(c=='-') f=-1ll;
        c=getchar();
    }
    while(isdigit(c)){
        t=(t<<3ll)+(t<<1ll)+ll(c-'0');
        c=getchar();
    }
    return t*f;
}
const int maxn=109;
const ll mod=1e9+7;
int n;
ll k;
struct matrix{
    int a,b;
    ll x[maxn][maxn];
    inline matrix operator*(const matrix A)const{
        matrix B;B.clear();B.a=a;B.b=A.b;
        rep(i,1,a){
            rep(j,1,A.b){
                rep(k,1,b) B.x[i][j]=(B.x[i][j]+x[i][k]*A.x[k][j])%mod;
            }
        }
        return B;
    }
     inline matrix operator^(const ll k)const{
        ll t=k;matrix A,B;
        A.a=B.a=a;A.b=B.b=b;
        rep(i,1,a)
            rep(j,1,b) A.x[i][j]=x[i][j];
        B.clear();
        rep(i,1,a) B.x[i][i]=1;
        while(t){
            if(t&1) B=B*A;
            A=A*A;t>>=1ll;
        }
        return B;
    }
    inline void clear(){
        rep(i,1,a)
            rep(j,1,b) x[i][j]=0;
    }
    inline void in(int _a,int _b){
        a=_a;b=_b;
        rep(i,1,_a)
            rep(j,1,_b) x[i][j]=readint();
    }
    inline void out(){
        rep(i,1,a){
            rep(j,1,b){
                printf("%lld",x[i][j]);
                putchar(j==b?'\n':' ');
            }
        }
    }
}X;
int main(){
    //freopen("#intput.txt","r",stdin);
    //freopen("#output.txt","w",stdout);
    n=readint();k=readll();X.in(n,n);     
    matrix Ans=X^k;
    Ans.out();
    //fclose(stdin);
    //fclose(stdout);
    return 0;
}