jdk1.8特性2
public class User {
private Long id;
private String userName;
private String roleName;
private String password;
private Integer age;
private Integer gender;
private String nickName;
private Double salary;
private StatsType Type;
/**
*
* @param id
* @param userName
* @param roleName
* @param password
* @param age
* @param gender
* @param nickName
* @param salary
* @param Type
*/
public User(Long id,String userName,String roleName,String password,Integer age,Integer gender,String nickName,Double salary,StatsType Type) {
this.id = id;
this.userName = userName;
this.roleName = roleName;
this.password = password;
this.age = age;
this.gender = gender;
this.nickName = nickName;
this.salary = salary;
this.Type = Type;
}
/**
* 分段类型
*/
public static enum StatsType {
OFFLINE((short) 0), NOTWORK((short) 1), WORKING((short) 2);
private short value;
private StatsType(short value) {
this.value = value;
}
public void setValue(short value) {
this.value = value;
}
public short getValue() {
return value;
}
public static StatsType valueOf(Short value) {
if (value == null) {
return null;
}
switch (value) {
case 0:
return OFFLINE;// 缺勤
case 1:
return NOTWORK;// 闲置
case 2:
return WORKING;// 工作
}
return null;
}
}
get,set.....
}
List<User> list2 = Lists.newArrayList( new User(1L,"sa","职员","***",18,0,"张三",13242.69,User.StatsType.NOTWORK), new User(2L,"yunying","职员","***",30,1,"李四",12746.36,User.StatsType.WORKING), new User(3L,"ta","经理","***",50,0,"王五",15312.98,User.StatsType.OFFLINE) );
取出对象中某个属性值
private static List<String> getUserName(List<User> list) {
return list.stream().map(User::getUserName).collect(Collectors.toList());
}
List<User> 分组(根据性别)
private static Map<Integer, List<User>> getGroupMapByGender(List<User> userList) {
return userList.stream().collect(Collectors.groupingBy(User::getGender));
}
Map<Integer, List<User>> map = getGroupMapByGender(list2);
for (Integer key : map.keySet()) {
System.out.println(key + "---" + JSONArray.toJSONString((List<User>) map.get(key)));
}
求两个数组的交集
String str = "a,b,c,d,e";
String str1 = "a,b,c,d,e,f,g";
List<String> list = Arrays.asList(str.split(","));
List<String> list1 = Arrays.asList(str1.split(","));
private static List<String> getMixList(List<String> orgList, List<String> deskList) {
return orgList.stream().filter(t -> deskList.contains(t)).collect(Collectors.toList());
}
对map的value进行排序
Map<String, Integer> mapData = new HashMap<>();
mapData.put("aa", 20);
mapData.put("bb", 7);
mapData.put("cc", 10);
private static Map<String, Integer> sortOrderByMapValue(Map<String, Integer> map) {
return map.entrySet().stream().sorted(Map.Entry.<String, Integer> comparingByValue())
.collect(Collectors.toMap(k -> k.getKey(), v -> v.getValue(), (k, v) -> k, LinkedHashMap::new));
}
List转Map(抽取某一属性做value)
private static Map<String, String> getList2Map(List<User> list) {
return list.stream().collect(Collectors.toMap(User::getUserName, User::getNickName));
}
List转Map(value为对象本身)
private static Map<String, User> getList2Map2(List<User> list) {
return list.stream()
.collect(Collectors.toMap(User::getUserName, User -> User, (key1, key2) -> key2, LinkedHashMap::new));
}
数组中某属性最大值
private static Optional<User> getMaxAgeByList(List<User> list) {
return list.stream().max((e1, e2) -> Integer.compare(e1.getAge(), e2.getAge()));
}
分组查询职员数量
Map<String,Long> map5 = list2.stream()
.collect(Collectors.groupingBy(User::getRoleName,Collectors.counting()));
System.out.println(map5);
数组中返回的第一个元素
private static Optional<User> getFirstValueByList(List<User> list) {
return list.stream().findFirst();
}
数组中属性是否有某值(是否所有人都没在工作)
private static boolean isHasNoneValueByList(List<User> list) {
return list.stream().noneMatch((e) -> e.getType().equals(User.StatsType.WORKING));
}
数组中属性是否有某值(是否所有人都在工作)
private static boolean isHasAllValueByList(List<User> list) {
return list.stream().allMatch((e) -> e.getType().equals(User.StatsType.WORKING));
}
数组中属性是否有某值(是否有人没来)
private static boolean isHasAnyValueByList(List<User> list) {
return list.stream().anyMatch((e) -> e.getType().equals(User.StatsType.OFFLINE));
}
数组中某属性最小值
private static Optional<User> getMinAgeByList(List<User> list2) {
return list2.stream().min((e1, e2) -> Integer.compare(e1.getAge(), e2.getAge()));
}
System.out.println(user4.get().getAge());
浙公网安备 33010602011771号