175.Mysql之组合两个表

表1: Person

+-------------+---------+
| 列名         | 类型     |
+-------------+---------+
| PersonId    | int     |
| FirstName   | varchar |
| LastName    | varchar |
+-------------+---------+
PersonId 是上表主键

表2: Address

+-------------+---------+
| 列名         | 类型    |
+-------------+---------+
| AddressId   | int     |
| PersonId    | int     |
| City        | varchar |
| State       | varchar |
+-------------+---------+
AddressId 是上表主键

 

编写一个 SQL 查询,满足条件:无论 person 是否有地址信息,都需要基于上述两表提供 person 的以下信息:

 

FirstName, LastName, City, State

解决方案:
  使用left join左关联
select t1.FirstName,t1.LastName,t2.City,t2.State
from Person t1
left join Address t2 on t1.PersonId = t2.PersonId

 

 
posted @ 2018-12-01 14:48  卓别林铲屎官  阅读(187)  评论(0)    收藏  举报