Leetcode 144. 二叉树的前序遍历
给定一个二叉树,返回它的 前序 遍历。
示例:
输入: [1,null,2,3]
1
\
2
/
3
输出: [1,2,3]
进阶: 递归算法很简单,你可以通过迭代算法完成吗?
//前序递归 class Solution { public: vector<int> res; vector<int> preorderTraversal(TreeNode* root) { pre(root); return res; } void pre(TreeNode *root) { if (root == nullptr) return; res.push_back(root->val); pre(root->left); pre(root->right); } };
/Morris Traversal算法
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * }; */ class Solution { public: vector<int> preorderTraversal(TreeNode* root) { vector<int> res; while (root) { if (!root->left) { res.push_back(root->val); root = root->right; } else { TreeNode *pre = root->left; while (pre->right && pre->right != root) pre = pre->right; if (pre->right) pre->right = 0, root = root->right; else { pre->right = root; res.push_back(root->val); root = root->left; } } } return res; } };

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