Leetcode 144. 二叉树的前序遍历

给定一个二叉树,返回它的 前序 遍历。

 示例:

输入: [1,null,2,3]  
   1
    \
     2
    /
   3 

输出: [1,2,3]

进阶: 递归算法很简单,你可以通过迭代算法完成吗?

//前序递归
class Solution {
public:
    vector<int> res;
    vector<int> preorderTraversal(TreeNode* root) {
        pre(root);
        return res;
    }
    void pre(TreeNode *root)
    {
        if (root == nullptr) return;
        res.push_back(root->val);
        pre(root->left);
        pre(root->right);
    }
};
/Morris Traversal算法
/*
* * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * }; */ class Solution { public: vector<int> preorderTraversal(TreeNode* root) { vector<int> res; while (root) { if (!root->left) { res.push_back(root->val); root = root->right; } else { TreeNode *pre = root->left; while (pre->right && pre->right != root) pre = pre->right; if (pre->right) pre->right = 0, root = root->right; else { pre->right = root; res.push_back(root->val); root = root->left; } } } return res; } };

 

posted @ 2020-10-27 22:22  。啊这  阅读(77)  评论(0)    收藏  举报