第六次上机作业

task 4

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define  N 100

typedef  struct { 
    char num[10];
    int s1;
    int s2;
    double sum;
    char level[10];
} STU;


int fun(STU a[], int n, STU h[]);

int main() {
   STU s[N]={ {"GA05", 85, 76}, 
              {"GA03", 76, 90}, 
              {"GA02", 69, 90}, 
              {"GA04", 85, 56}, 
              {"GA01", 91, 95},
              {"GA07", 72, 80}, 
              {"GA08", 64, 45}, 
              {"GA06", 87, 98}, 
              {"GA015", 85, 86}, 
              {"GA013", 91, 97} };
    STU h[N];
    int i, k, n = 10; 

    k = fun(s, n, h);

    printf("There are :\n");
    for(i = 0; i < k; i++)
        printf("%s %d %d %.2f %s\n", h[i].num, h[i].s1, h[i].s2, h[i].sum, h[i].level);
        
    system("pause");
    return 0;
}

int fun(STU a[],int n,STU h[]){
    int i,j,k = 0;
    double sum;
    for(j = 0;j < n;j++)
    {
        a[j].sum = a[j].s1*0.7 + a[j].s2*0.3;
        sum = sum + a[j].sum;
    }
    
    for(i = 0;i < n;i++)
    {
        if(a[i].sum>sum/n){
        strcpy(a[i].level,"均分以上");
        h[k++] = a[i];}
    }
    return k;
}

task 5

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define N 5

typedef struct student {
    char name[10];
    int num;
    int maths;
    int computer;
    int english;
    int sum;
    char level[10];
} STU;

void fun(STU a[], int n);

int main() {
    STU s[6*N]={ {"A001", 1, 34, 67, 80},
                 {"B003", 3, 78, 87, 90},
                 {"A002", 2, 90, 98, 99},
                 {"B002", 4, 56, 78, 98},
                 {"A005", 5, 35, 67, 79} };
    int i;

    fun(s, N);
    for(i = 0; i < N; i++)
      printf("%s %d %d %d %d %d %s\n", s[i].name, s[i].num, s[i].maths, s[i].computer, s[i].english, s[i].sum, s[i].level);
      
    system("pasue");
    return 0;
}

void fun(STU a[], int n) {
int i,j,k;
double min,max;
for(i=0;i<n;i++)
{
    a[i].sum = a[i].maths + a[i].computer + a[i].english;
}

max = a[0].sum;
min = a[0].sum;

for(j=0;j<n;j++){
    if( max < a[j].sum)
    max = a[j].sum;
    if(min > a[j].sum)
    min = a[j].sum;
}

for(k=0;k<n;k++)
{
    if(a[k].sum == min)
    strcpy(a[k].level,"不及格");
    else if(a[k].sum == max)
    strcpy(a[k].level,"优秀");
    else
    strcpy(a[k].level,"合格"); 
}

}

task 6

#include <stdio.h>
#include<stdlib.h>
#define N 5

typedef struct student {
    long no;
    char name[20];
    int score;
} STU;

void input(STU s[], int n);
int find_min_list(STU s[], STU t[], int n);
void output(STU s[], int n);

int main() {
    STU stu[N], min_list[N];
    int count;

    printf("录入%d个学生信息\n", N);
    input(stu, N);

    printf("\n统计最低分人数和学生信息...\n");
    count = find_min_list(stu, min_list, N);

    printf("\n一共有%d个最低分,信息如下:\n", count);
    output(min_list, count);
    
    system("pause");
    return 0;
}

void input(STU s[], int n) {
    int i;
    for(i=0;i<n;i++)
    {
        scanf("%ld %s %d",&s[i].no,s[i].name,&s[i].score);
    }
}

void output(STU s[], int n) {
    int j;
    for(j=0;j<n;j++)
    {
        printf("%ld %s %d\n",s[j].no,s[j].name,s[j].score);
    }
}

int find_min_list(STU s[], STU t[], int n) {
    int i,j,k,r=0;
    double min;
    min = s[0].score;
    for(k=0;k<n;k++)
    {
        if(s[k].score<min)
        min = s[k].score;
        
    }
    
    for(k=0;k<n;k++)
    {
        if(s[k].score == min)
        t[r++] = s[k];
    }
    return r;
}

 

posted @ 2023-05-25 18:14  chen,,  阅读(5)  评论(0编辑  收藏  举报