195 Tenth Line

How would you print just the 10th line of a file?

For example, assume that file.txt has the following content:

Line 1
Line 2
Line 3
Line 4
Line 5
Line 6
Line 7
Line 8
Line 9
Line 10

Your script should output the tenth line, which is:

Line 10

[show hint]

Hint:
1. If the file contains less than 10 lines, what should you output?
2. There's at least three different solutions. Try to explore all possibilities.

 

# Solution 1
cnt=0
while read line && [ $cnt -le 10 ]; do
  let 'cnt = cnt + 1'
  if [ $cnt -eq 10 ]; then
    echo $line
    exit 0
  fi
done < file.txt

# Solution 2
awk 'FNR == 10 {print }'  file.txt
# OR
awk 'NR == 10' file.txt

# Solution 3
sed -n 10p file.txt

# Solution 4
tail -n+10 file.txt|head -1