实验六

实验4

 1 #include <stdio.h>
 2 #include <string.h>
 3 #define N 10
 4 
 5 typedef struct {
 6     char isbn[20];
 7     char name[80];
 8     char author[80];
 9     double sales_price;
10     int sales_count;
11 } Book;
12 
13 void output(Book x[], int n);
14 void sort(Book x[], int n);
15 double sales_amount(Book x[], int n);
16 
17 int main() {
18     Book x[N] = {
19         {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
20         {"978-7-308-17047-5", "自由与爱之地:入以色列记", "云也退", 49, 30},
21         {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
22         {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
23         {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
24         {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
25         {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
26         {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
27         {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
28         {"978-7-229-14156-1", "源泉", "安·兰德", 84, 59}
29     };
30 
31     printf("图书销量排名(按销售册数):\n");
32     sort(x, N);
33     output(x, N);
34     printf("\n图书销售总额:%.2f\n", sales_amount(x, N));
35 
36     return 0;
37 }
38 
39 void output(Book x[], int n) {
40     printf("ISBN号\t\t\t书名\t\t\t\t\t作者\t\t\t售价\t销售册数\n");
41     int i;
42     for (i = 0; i < n; i++) {
43         printf("%s\t%s\t%s\t%.1f\t%d\n", x[i].isbn, x[i].name, x[i].author, x[i].sales_price, x[i].sales_count);
44     }
45 }
46 
47 void sort(Book x[], int n) {
48     int i, j;
49     Book temp;
50     for (i = 0; i < n - 1; i++) {
51         for (j = 0; j < n - 1 - i; j++) {
52             if (x[j].sales_count < x[j+1].sales_count) {
53                 temp = x[j];
54                 x[j] = x[j+1];
55                 x[j+1] = temp;
56             }
57         }
58     }
59 }
60 
61 double sales_amount(Book x[], int n) {
62     double total = 0.0;
63     int i;
64     for (i = 0; i < n; i++) {
65         total += x[i].sales_price * x[i].sales_count;
66     }
67     return total;
68 }

屏幕截图 2025-12-24 180739

 

 

 

实验5

 1 #include <stdio.h>
 2 
 3 typedef struct {
 4     int year;
 5     int month;
 6     int day;
 7 } Date;
 8 
 9 void input(Date *pd);
10 int day_of_year(Date d);
11 int compare_dates(Date d1, Date d2);
12 
13 void test1() {
14     Date d;
15     int i;
16     printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
17     for(i = 0; i < 3; ++i) {
18         input(&d);
19         printf("%d-%02d-%02d是这一年中第%d天\n", d.year, d.month, d.day, day_of_year(d));
20     }
21 }
22 
23 void test2() {
24     Date Alice_birth, Bob_birth;
25     int i;
26     int ans;
27     printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
28     for(i = 0; i < 3; ++i) {
29         input(&Alice_birth);
30         input(&Bob_birth);
31         ans = compare_dates(Alice_birth, Bob_birth);
32         if(ans == 0)
33             printf("Alice和Bob一样大\n");
34         else if(ans == -1)
35             printf("Alice比Bob大\n");
36         else
37             printf("Alice比Bob小\n");
38     }
39 }
40 
41 int main() {
42     printf("测试1: 输入日期,打印输出这是一年中第多少天\n");
43     test1();
44     printf("\n测试2: 两个人年龄大小关系\n");
45     test2();
46     return 0;
47 }
48 
49 void input(Date *pd) {
50     scanf("%d-%d-%d", &pd->year, &pd->month, &pd->day);
51 }
52 
53 int day_of_year(Date d) {
54     int days[] = {31,28,31,30,31,30,31,31,30,31,30,31};
55     int total = 0;
56     int i;
57     if((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0)) {
58         days[1] = 29;
59     }
60     for(i = 0; i < d.month - 1; i++) {
61         total += days[i];
62     }
63     total += d.day;
64     return total;
65 }
66 
67 int compare_dates(Date d1, Date d2) {
68     if(d1.year < d2.year) {
69         return -1;
70     } else if(d1.year > d2.year) {
71         return 1;
72     } else {
73         int day1 = day_of_year(d1);
74         int day2 = day_of_year(d2);
75         if(day1 < day2) {
76             return -1;
77         } else if(day1 > day2) {
78             return 1;
79         } else {
80             return 0;
81         }
82     }
83 }

屏幕截图 2025-12-24 181406

 

 

实验6

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 enum Role {admin, student, teacher};
 5 
 6 typedef struct {
 7     char username[20];
 8     char password[20];
 9     enum Role type;
10 } Account;
11 
12 void output(Account x[], int n);
13 
14 int main() {
15     Account x[] = {
16         {"A1001", "123456", student},
17         {"A1002", "123abcdef", student},
18         {"A1009", "xyz12121", student},
19         {"X1009", "9213071x", admin},
20         {"C11553", "129dfg32k", teacher},
21         {"X3005", "921kfmg917", student}
22     };
23     int n;
24     n = sizeof(x)/sizeof(Account);
25     output(x, n);
26     return 0;
27 }
28 
29 void output(Account x[], int n) {
30     int i, j;
31     char *role_name;
32     for(i = 0; i < n; i++) {
33         printf("%s\t\t", x[i].username);
34         for(j = 0; j < strlen(x[i].password); j++) {
35             printf("*");
36         }
37         printf("\t\t");
38         switch(x[i].type) {
39             case admin: role_name = "admin"; break;
40             case student: role_name = "student"; break;
41             case teacher: role_name = "teacher"; break;
42             default: role_name = "unknown";
43         }
44         printf("%s\n", role_name);
45     }
46 }

屏幕截图 2025-12-24 181855

 

 

实验7

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 typedef struct {
 5     char name[20];
 6     char phone[12];
 7     int vip;
 8 } Contact;
 9 
10 void set_vip_contact(Contact x[], int n, char name[]);
11 void output(Contact x[], int n);
12 void display(Contact x[], int n);
13 
14 #define N 10
15 
16 int main() {
17     Contact list[N] = {
18         {"刘一", "15510846604", 0},
19         {"陈二", "18038747351", 0},
20         {"张三", "18853253914", 0},
21         {"李四", "13230584477", 0},
22         {"王五", "15547571923", 0},
23         {"赵六", "18856659351", 0},
24         {"周七", "17705843215", 0},
25         {"孙八", "15552933732", 0},
26         {"吴九", "18077702405", 0},
27         {"郑十", "18820725036", 0}
28     };
29     int vip_cnt, i;
30     char name[20];
31 
32     printf("显示原始通讯录信息:\n");
33     output(list, N);
34 
35     printf("\n输入要设置的紧急联系人个数:");
36     scanf("%d", &vip_cnt);
37 
38     printf("输入%d个紧急联系人姓名:\n", vip_cnt);
39     for(i = 0; i < vip_cnt; ++i) {
40         scanf("%s", name);
41         set_vip_contact(list, N, name);
42     }
43 
44     printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
45     display(list, N);
46 
47     return 0;
48 }
49 
50 void set_vip_contact(Contact x[], int n, char name[]) {
51     int i;
52     for(i = 0; i < n; i++) {
53         if(strcmp(x[i].name, name) == 0) {
54             x[i].vip = 1;
55             break;
56         }
57     }
58 }
59 
60 void output(Contact x[], int n) {
61     int i;
62     for(i = 0; i < n; ++i) {
63         printf("%-10s%-15s", x[i].name, x[i].phone);
64         if(x[i].vip) {
65             printf("%5s", "*");
66         }
67         printf("\n");
68     }
69 }
70 
71 void display(Contact x[], int n) {
72     Contact temp, sorted[N];
73     int i, j, k = 0;
74 
75     for(i = 0; i < n; i++) {
76         sorted[i] = x[i];
77     }
78 
79     for(i = 0; i < n - 1; i++) {
80         for(j = 0; j < n - 1 - i; j++) {
81             if(sorted[j].vip < sorted[j+1].vip) {
82                 temp = sorted[j];
83                 sorted[j] = sorted[j+1];
84                 sorted[j+1] = temp;
85             } else if(sorted[j].vip == sorted[j+1].vip) {
86                 if(strcmp(sorted[j].name, sorted[j+1].name) > 0) {
87                     temp = sorted[j];
88                     sorted[j] = sorted[j+1];
89                     sorted[j+1] = temp;
90                 }
91             }
92         }
93     }
94 
95     output(sorted, n);
96 }

屏幕截图 2025-12-24 182241

 

posted @ 2025-12-24 18:23  cchheenn  阅读(3)  评论(0)    收藏  举报