实验五
实验1
1 #include <stdio.h> 2 #define N 5 3 4 void input(int x[], int n); 5 void output(int x[], int n); 6 void find_min_max(int x[], int n, int *pmin, int *pmax); 7 8 int main() { 9 int a[N]; 10 int min, max; 11 12 printf("录入%d个数据:\n", N); 13 input(a, N); 14 15 printf("数据是: \n"); 16 output(a, N); 17 18 printf("数据处理...\n"); 19 find_min_max(a, N, &min, &max); 20 21 printf("输出结果:\n"); 22 printf("min = %d, max = %d\n", min, max); 23 24 return 0; 25 } 26 27 void input(int x[], int n) { 28 int i; 29 30 for(i = 0; i < n; ++i) 31 scanf("%d", &x[i]); 32 } 33 34 void output(int x[], int n) { 35 int i; 36 37 for(i = 0; i < n; ++i) 38 printf("%d ", x[i]); 39 printf("\n"); 40 } 41 42 void find_min_max(int x[], int n, int *pmin, int *pmax) { 43 int i; 44 45 *pmin = *pmax = x[0]; 46 47 for(i = 0; i < n; ++i) 48 if(x[i] < *pmin) 49 *pmin = x[i]; 50 else if(x[i] > *pmax) 51 *pmax = x[i]; 52 }

作用:历遍数组 找到最大和最小值
pmin指向主函数中min的指针
pmax指向主函数中max的指针
#include <stdio.h> #define N 5 void input(int x[], int n); void output(int x[], int n); int *find_max(int x[], int n); int main() { int a[N]; int *pmax; printf("录入%d个数据:\n", N); input(a, N); printf("数据是: \n"); output(a, N); printf("数据处理...\n"); pmax = find_max(a, N); printf("输出结果:\n"); printf("max = %d\n", *pmax); return 0; } void input(int x[], int n) { int i; for(i = 0; i < n; ++i) scanf("%d", &x[i]); } void output(int x[], int n) { int i; for(i = 0; i < n; ++i) printf("%d ", x[i]); printf("\n"); } int *find_max(int x[], int n) { int max_index = 0; int i; for(i = 0; i < n; ++i) if(x[i] > x[max_index]) max_index = i; return &x[max_index]; }

功能:历遍数组中所有元素 找到最大值并返回其地址
可以 历遍数组后ptr更新为最大元素的地址
实验2
1 #include <stdio.h> 2 #include <string.h> 3 #define N 80 4 5 int main() { 6 char s1[N] = "Learning makes me happy"; 7 char s2[N] = "Learning makes me sleepy"; 8 char tmp[N]; 9 10 printf("sizeof(s1) vs. strlen(s1): \n"); 11 printf("sizeof(s1) = %d\n", sizeof(s1)); 12 printf("strlen(s1) = %d\n", strlen(s1)); 13 14 printf("\nbefore swap: \n"); 15 printf("s1: %s\n", s1); 16 printf("s2: %s\n", s2); 17 18 printf("\nswapping...\n"); 19 strcpy(tmp, s1); 20 strcpy(s1, s2); 21 strcpy(s2, tmp); 22 23 printf("\nafter swap: \n"); 24 printf("s1: %s\n", s1); 25 printf("s2: %s\n", s2); 26 27 return 0; 28 }

s1大小:80
sizeof(s1):计算字符组s1所占的总字节数
strlen(s1):字符串中实际有效的字节数
不能 s1是地址常量,不能被赋值
是
1 #include <stdio.h> 2 #include <string.h> 3 #define N 80 4 5 int main() { 6 char *s1 = "Learning makes me happy"; 7 char *s2 = "Learning makes me sleepy"; 8 char *tmp; 9 10 printf("sizeof(s1) vs. strlen(s1): \n"); 11 printf("sizeof(s1) = %d\n", sizeof(s1)); 12 printf("strlen(s1) = %d\n", strlen(s1)); 13 14 printf("\nbefore swap: \n"); 15 printf("s1: %s\n", s1); 16 printf("s2: %s\n", s2); 17 18 printf("\nswapping...\n"); 19 tmp = s1; 20 s1 = s2; 21 s2 = tmp; 22 23 printf("\nafter swap: \n"); 24 printf("s1: %s\n", s1); 25 printf("s2: %s\n", s2); 26 27 return 0; 28 }

s1:字符串在内存中的首地址
sizeof(s1):字符指针变量本身的大小
strlen(s1):到‘\0’结束的字符个数
可以 原来是定义指针变量的同时初始化 现在是先定义指针变量 再单独赋值
s1和s2存储的地址值
不会
实验3
1 #include <stdio.h> 2 3 int main() { 4 int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}}; 5 int i, j; 6 int *ptr1; 7 int(*ptr2)[4]; 8 printf("输出1: 使用数组名、下标直接访问二维数组元素\n"); 9 for (i = 0; i < 2; ++i) { 10 for (j = 0; j < 4; ++j) 11 printf("%d ", x[i][j]); 12 printf("\n"); 13 } 14 15 printf("\n输出2: 使用指针变量ptr1(指向元素)间接访问\n"); 16 for (ptr1 = &x[0][0], i = 0; ptr1 < &x[0][0] + 8; ++ptr1, ++i) { 17 printf("%d ", *ptr1); 18 19 if ((i + 1) % 4 == 0) 20 printf("\n"); 21 } 22 23 printf("\n输出3: 使用指针变量ptr2(指向一维数组)间接访问\n"); 24 for (ptr2 = x; ptr2 < x + 2; ++ptr2) { 25 for (j = 0; j < 4; ++j) 26 printf("%d ", *(*ptr2 + j)); 27 printf("\n"); 28 } 29 30 return 0; 31 }

包含四个int数据类型元素的一维数组的指针
包含四个int数据类型元素的一维数组
实验4
1 #include <stdio.h> 2 #define N 80 3 4 void replace(char *str, char old_char, char new_char); 5 int main() { 6 char text[N] = "Programming is difficult or not, it is a question."; 7 8 printf("原始文本: \n"); 9 printf("%s\n", text); 10 11 replace(text, 'i', '*'); 12 13 printf("处理后文本: \n"); 14 printf("%s\n", text); 15 16 return 0; 17 } 18 19 void replace(char *str, char old_char, char new_char) { 20 int i; 21 22 while(*str) { 23 if(*str == old_char) 24 *str = new_char; 25 str++; 26 } 27 }

replace:将所有的old_char 换成 new_char
可以
实验5
#include <stdio.h> #define N 80 char *str_trunc(char *str, char x) { char *p = str; while (*p != '\0') { if (*p == x) { *p = '\0'; break; } p++; } return str; 句) } int main() { char str[N]; char ch; char *result; while (1) { printf("输入字符串:"); scanf("%s", str); printf("输入一个字符:"); getchar(); ch = getchar(); printf("截断处理...\n"); result = str_trunc(str, ch); printf("截断处理后的字符串:%s\n\n", result); printf("是否继续?(y/n):"); ch = getchar(); getchar(); if (ch != 'y' && ch != 'Y') { break; } } return 0; }

跳过输入字符的步骤 存放\n
实验六
#include <stdio.h> #include <string.h> #define N 5 int check_id(char *str); int main() { char *pid[N] = {"31010120000721656X", "3301061996X0203301", "53010220051126571", "510104199211197977", "53010220051126133Y"}; int i; for (i = 0; i < N; ++i) { if (check_id(pid[i])) printf("%s\tTrue\n", pid[i]); else printf("%s\tFalse\n", pid[i]); } return 0; } int check_id(char *str) { int len = strlen(str); char *p = str; if (len != 18) return 0; while (p < str + 17) { if (*p < '0' || *p > '9') return 0; p++; } if ((*p >= '0' && *p <= '9') || *p == 'X' || *p == 'x' || *p == 'Y' || *p == 'y') return 1; else return 0; }

实验七
1 #include <stdio.h> 2 #define N 80 3 4 void encoder(char *str, int n); 5 void decoder(char *str, int n); 6 7 int main() { 8 char words[N]; 9 int n; 10 11 printf("输入英文文本: "); 12 gets(words); 13 14 printf("输入n: "); 15 scanf("%d", &n); 16 17 printf("编码后的英文文本: "); 18 encoder(words, n); 19 printf("%s\n", words); 20 21 printf("对编码后的英文文本解码: "); 22 decoder(words, n); 23 printf("%s\n", words); 24 25 return 0; 26 } 27 28 void encoder(char *str, int n) { 29 char *p = str; 30 n = n % 26; 31 while (*p != '\0') { 32 if (*p >= 'a' && *p <= 'z') { 33 *p = (*p - 'a' + n) % 26 + 'a'; 34 } else if (*p >= 'A' && *p <= 'Z') { 35 *p = (*p - 'A' + n) % 26 + 'A'; 36 } 37 p++; 38 } 39 } 40 41 void decoder(char *str, int n) { 42 char *p = str; 43 n = n % 26; 44 while (*p != '\0') { 45 if (*p >= 'a' && *p <= 'z') { 46 *p = (*p - 'a' - n + 26) % 26 + 'a'; 47 } else if (*p >= 'A' && *p <= 'Z') { 48 *p = (*p - 'A' - n + 26) % 26 + 'A'; 49 } 50 p++; 51 } 52 }



实验八
#include <stdio.h> #include <string.h> int main(int argc, char *argv[]) { int i, j; char *tmp; if (argc < 2) { printf("请输入参数!\n"); return 1; } for (i = 1; i < argc - 1; ++i) { for (j = i + 1; j < argc; ++j) { if (strcmp(argv[i], argv[j]) > 0) { tmp = argv[i]; argv[i] = argv[j]; argv[j] = tmp; } } } for (i = 1; i < argc; ++i) { printf("hello, %s\n", argv[i]); } return 0; }
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