牛客网编程练习之PAT乙级(Basic Level)：1034 写出这个数

 

AC代码：

import java.util.*;

/**
 * @author CC11001100
 */
public class Main {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);
		String s = sc.nextLine();
		System.out.println(toPinYin(sum(s)));

	}

	private static int sum(String s){
		int res = 0;
		for(int i=0; i<s.length(); i++){
			res += s.charAt(i) - '0';
		}
		return res;
	}

	private static Map<Integer, String> map = new HashMap<>();

	static{
		map.put(0, "ling");
		map.put(1, "yi");
		map.put(2, "er");
		map.put(3, "san");
		map.put(4, "si");
		map.put(5, "wu");
		map.put(6, "liu");
		map.put(7, "qi");
		map.put(8, "ba");
		map.put(9, "jiu");
	}

	private static String toPinYin(int n){
		if(n<=9) return map.get(n);
		else return toPinYin(n/10) + " " + map.get(n % 10);
	}

}

 

或者可以使用数组下标来对应，就不用map了，也是能够随机访问取到：

import java.util.*;

/**
 * @author CC11001100
 */
public class Main {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);
		String s = sc.nextLine();
		System.out.println(toPinYin(sum(s)));

	}

	private static int sum(String s){
		int res = 0;
		for(int i=0; i<s.length(); i++){
			res += s.charAt(i) - '0';
		}
		return res;
	}

	private static String[] mapping = new String[]{"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu" };

	private static String toPinYin(int n){
		if(n<=9) return mapping[n];
		else return toPinYin(n/10) + " " + mapping[n%10];
	}

}

 

题目来源： https://www.nowcoder.com/pat/2/problem/4068

 

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