leetcode-python-打家劫舍

从第三项开始,判断是第i项加上之前的i-2的和大还是i-1的和大

class Solution:
    def rob(self, nums: List[int]) -> int:
        if not nums:
            return 0 
        if len(nums) == 1:
            return nums[0]
        profit = [0] * len(nums)
        profit[0] = nums[0]
        profit[1] = max(nums[0],nums[1])
        for i in range(2,len(nums)):
            profit[i] = max(nums[i] + profit[i-2],profit[i-1])
        return profit[-1]

 

posted @ 2021-06-08 15:38  泊鸽  阅读(60)  评论(0)    收藏  举报