CSP模拟练习赛1 https://www.luogu.com.cn/contest/82861#problems

P1321 单词覆盖还原 简单思路 字符串

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#include<map>
#define ll long long
using namespace std;
string s;
int cnta, cntb;
int main(){
    cin>>s;
    int len = s.length();
    for(int i = 0; i < len; i++){
        if(s[i] == 'b' || s[i+1] == 'o' || s[i+2] == 'y')
             cnta++;
        if(s[i] == 'g' || s[i+1] == 'i' || s[i+2] == 'r' || s[i+3] == 'l')
            cntb++;
    }
    cout<<cnta<<endl;
    cout<<cntb<<endl;
    return 0;
}

P1885 Moo 递归

// 3
// 3 + 1 + 3 + 3 = 10
// 3 + 1 + 3 + 3 +（1+4）+ 3 + 1 + 3 + 3 = 15
// 3 + 1 + 3 + 3 +（1+4）+ 3 + 1 + 3 + 3  +  （1+5）   + 3 + 1 + 3 + 3 +（1+4）+ 3 + 1 + 3 + 3
// 15 + 6 + 15 = 36
#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<queue>
using namespace std;
int s[30];
char f(int n, int t){
    if(t == 0){
        if(n == 1) return 'm';
        else return 'o';
    }
    int la = (s[t] - (1 + t + 2))/2 ;
    int lb = la + (1 + t + 2);
    if(n == la + 1) return 'm';
    else if(n > la+1 && n <= lb) return 'o';
    else if(n > lb) return f(n - lb, t-1);
    else return f(n, t-1);
}
int main(){
    int n,t; scanf("%d",&n);
    s[0] = 3;
    for(int i = 1; ;i++){
        s[i] = s[i-1] * 2 + 1 + i + 2;
        if(s[i] >= n){//s[i] >= 1000000000
            t = i; break;
        }
    }
    // cout<<t<<endl;
    cout<<f(n, t)<<endl;
    return 0;
}

单词接龙 字符串+dfs

#include<bits/stdc++.h>
using namespace std;
char a[105][105];
int n,side[105][105],vis[105],mx=-2147483647;
void h(int i,int j){
	int leni=strlen(a[i]+1);
	int lenj=strlen(a[j]+1);
	int l=0,len=leni<lenj?leni:lenj;
	while(l<=len){
		l++; int k;
		for(k=1;k<=l;k++){//
			if(a[i][leni-l+k]!=a[j][k]) break;
		}
		if(k==l+1){//
			side[i][j]=lenj-l;
//			cout<<"hhh: "<<a[i]+1<<" "<<a[j]+1<<" "<<side[i][j]<<endl;
			break;
		}
	}
	if(i>j) h(j,i);
}
void dfs(int x,int len){
	mx=max(len, mx);
	for(int i=1;i<=n;i++){//
		if(side[x][i]>0&&vis[i]<2){//一遍没用过，或者用过一遍，可以再用一次 
			vis[i]++;
			dfs(i,len+side[x][i]);
			vis[i]--;
		}
	}
}
int main(){
	cin>>n;
	for(int i=1;i<=n+1;i++){
		cin>>a[i]+1;
		for(int j=1;j<=i;j++){
			h(i,j);
		}
	}
	dfs(n+1,1);
	cout<<mx;
	return 0;
}

T271711 斯诺登的密码 https://www.luogu.com.cn/problem/T271711?contestId=82861

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#include<map>
#define ll long long
using namespace std;
string x;
int cnt , a[10], vis[10], b[10];
ll ans = 0xffffffffffff;
map<string, int> mp;
void dfs(int t, ll sum){
    if(sum >= ans) return;
    if(t == cnt+1){
        if(sum < ans) ans = sum;
        return;
    }
    for(int i = 1; i <= cnt; i++){
        if(!vis[i]){
            vis[i] = 1;
            // dfs(t+1, b[i] == 1 ? sum * 1000 + a[i] : sum * 100 + a[i]);
            dfs(t+1, sum * 100 + a[i]);
            vis[i] = 0;
        }
    }
}
int main(){
    mp["one"] = mp["a"] = 1, mp["two"] = 2, mp["three"] = 3, mp["four"] = 4, mp["five"] = 5, mp["six"] = 6;
    mp["seven"] = 7, mp["eight"] = 8, mp["nine"] = 9, mp["ten"] = 10, mp["eleven"] = 11,mp["twelve"] = 12;
    mp["thirteen"] = 13, mp["fourteen"] = 14, mp["fifteen"] = 15, mp["sixtreen"] = 16, mp["seventeen"] = 17;
    mp["eighteen"] = 18, mp["nineteen"] = 19, mp["twenty"] = 20;
    for(int i = 1; i <= 6; i++){
        cin>>x;
        if(mp[x]){
            a[++cnt] = (mp[x] * mp[x]) % 100;
            // if(a[cnt] == 1 || a[cnt] == 4 || a[cnt] == 9) b[cnt] = 1;
        }
    }
    // cout<<"cnt"<<" "<<cnt<<endl;
    // cout<<a[1]<<" "<<a[2]<<endl;
    dfs(1, 0);
    cout<<ans<<endl;
    return 0;
}
/*
4 25 36
1 36 16
*/

P1308 [NOIP2011 普及组] 统计单词数

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
using namespace std;
char a[1000005], b[15];
int cnt,pos,fl;
int main(){
	cin.getline(b+1, 15);
	cin.getline(a+1, 1000005);
	int lenb = strlen(b+1); int lena = strlen(a+1);
	a[0] = ' '; b[0] = ' '; a[lena+1] = ' '; b[lenb+1] = ' ';
	lenb++; lena++;

	for(int i = 0; i < lena; i++)
		if(a[i] >= 65 && a[i] <= 90) a[i] = a[i] + 32;
	for(int i = 0; i < lenb; i++)
		if(b[i] >= 65 && b[i] <= 90) b[i] = b[i] + 32;

	for(int i = 0; i < lena; i++){
		for(int j = 0; j < lenb; j++){
			int k = 0;
			while(a[i+k] == b[j+k]){
				k++;
			}
			if(k-1 == lenb){
				if(fl == 0) pos = i;
				cnt++;
				j = 0;
				fl = 1;
			}
		}
	}
	if(fl)
		cout<<cnt<<" "<<pos<<endl;
	else cout<<-1<<endl;
	return 0;
}