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訂單最多的客戶 select customer_number from Orders group by customer_number having count(order_number) = ( select count(order_number) from Orders group by cus 阅读全文
posted @ 2023-04-25 15:36
Carl_ZhangJH
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摘要:
尋找用戶推薦人 select name from customer where referee_id <> 2 or referee_id is null 阅读全文
posted @ 2023-04-25 15:12
Carl_ZhangJH
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至少有5名直接下屬的經理 子查詢 select `name` from Employee where id in ( select managerId from Employee group by managerId having count(managerId) >= 5 ) 自連接 select 阅读全文
posted @ 2023-04-25 14:29
Carl_ZhangJH
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