leetcode 586 訂單最多的客戶

訂單最多的客戶

 

select customer_number from Orders
group by customer_number 
having count(order_number) = (
    select count(order_number) from Orders
    group by customer_number
    order by count(order_number) desc
    limit 0,1
)

 

posted @ 2023-04-25 15:36  Carl_ZhangJH  阅读(13)  评论(0)    收藏  举报