with ChildMenu as( select * from MemberMenu where MenuId='F31E3D26-BB08-42C0-A171-EF62243A94C6' union all select MemberMenu.* from MemberMenu inner join ChildMenu on MemberMenu.ParMenuId=ChildMenu.MenuId )
select * from ChildMenu
posted on
2011-12-06 10:57@清风......
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