关于dynamic_cast

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dynamic_cast 进行运行时强制转换。如果在执行时转换非法,则会转换失败。dynamic_cast 的通用形式如下:

dynamic_cast <target-type> (expr)


其中 target-type 指定了强制转换的目标类型expr 是需要进行强制转换的表达式。

目标类型必须是指针类型或引用类型,也就是说,表达式也必须能够被求值为指针类型或者引用类型的结果。

dynamic_cast 主要被用来执行多态类型之间的强制转换。比如两个多态类 B 和 D,且 D 派生于 B,此时我们可以用 dynamic_cast 将 D* 指针类型转换为 B* 类型,这是因为基类型的指针通常可以指向派生类的对象。然而,只有当指针指向的对象确实是类 D 的对象时,dynamic_cast 才能将指针从类型 D* 转换为类型 B* 。

如果转换指针的类型失败时,经过 dynamic_cast 运算后得到的指针为空值。
如果转换引用的类型失败时,则会抛出 bad_cast 类型异常。

下面示例中,假设 Base 是多态类,Derived 派生于 Base ,那么:

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Base *bp, b_ob;
Derived *dp, d_ob;
 
bp = &d_ob;           // 基类型的指针可以指向派生类的对象
 
dp = dynamic_cast<Derived *> (bp);   //强制转换基类指针为派生类指针,做法正确


上面,将基类指针 bp 强制转换为派生类指针 dp 是可以的,这是因为 bp 指向的对象确实是一个 Derived 类型的对象。

下面的是强制转换失败的示例:

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bp = &b_ob;
dp = dynamic_cast<Derived *>(bp);    //错误


现在 bp 是一个指向基类对象的指针,这时不能 dynamic_cast 将其强制转换为派生类对象的指针,因为派生类对象的指针不能指向基类的对象。

下面是代码测试多种 dynamic_cast 的情况:

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// dynamicast.cpp : 定义控制台应用程序的入口点。
//
 
#include "stdafx.h"
#include <iostream>
using namespace std;
 
class Base {
public:
    virtual void f() { cout << "Inside Base.\n"; }
};
 
class Derived : public Base {
public:
    void f() { cout << "Inside Derived\n"; }
};
 
int _tmain(int argc, _TCHAR* argv[])
{
    Base *bp, b_ob;
    Derived *dp, d_ob;
 
    dp = dynamic_cast<Derived *>(&d_ob);    //派生类对象的指针强制转换为派生类对象的指针 OK
    if (dp) {
        cout << "Cast from Derived * to Derived * OK.\n";
        dp->f();
    } else
        cout << "Error\n";
    cout << endl;
 
    bp = dynamic_cast<Base *>(&d_ob);  //派生类对象的指针强制转换为基类的指针 OK(基类指针可以指向派生类的对象)
    if (bp) {
        cout << "Cast from Derived * to Base * OK.\n";    
        bp->f();
    } else
        cout << "Error\n";
    cout << endl;
 
    bp = dynamic_cast<Base *>(&b_ob);   //基类的指针强制转换为基类的指针 OK
    if (bp) {
        cout << "Cast from Base * to Base * OK.\n";
        bp->f();
    } else
        cout << "Error\n";
    cout << endl;
 
    dp = dynamic_cast<Derived *>(&b_ob);    //基类对象的指针(地址)强制转换为派生类的指针(失败)
    if(dp)
        cout << "Error\n";
    else
        cout << "Cast from Base * to Derived * not OK.\n";
     
    cout << endl;
 
    bp = &d_ob;        //bp 指向派生类的对象
     
    dp = dynamic_cast<Derived *> (bp);       //可以,因为 bp 确实已经指向了派生类
    if(dp) {
        cout << "Casting bp to Derived * OK\n" << "because bp is really pointing\n"
             << "to a Derived object.\n";
             dp->f();
    }else
        cout << "Error\n";
    cout << endl;
 
    bp = &b_ob;        //bp 指向基类型对象
    dp = dynamic_cast<Derived *> (bp);  //失败,因为 bp 现在已经确实指向了基类对象
    if(dp)
        cout << "Error";
    else {
        cout << "Now casting bp to a Derived *\n"
              << "is not OK because bp is really \n"
              << "pointing to a Base object.\n";
    }
    cout << endl;
 
    dp = &d_ob;        //dp 指向派生类对象
    bp = dynamic_cast<Base *> (dp);    //可以,基类指针可以指向派生类对象
    if (bp) {
        cout << "Casting dp to a Base * is OK.\n";
        bp->f();
    }else
        cout << "Error\n";
 
    return 0;
}


运行输出:

Cast from Derived * to Derived * OK.
Inside Derived

Cast from Derived * to Base * OK.
Inside Derived

Cast from Base * to Base * OK.
Inside Base.

Cast from Base * to Derived * not OK.

Casting bp to Derived * OK
because bp is really pointing
to a Derived object.
Inside Derived

Now casting bp to a Derived *
is not OK because bp is really
pointing to a Base object.

Casting dp to a Base * is OK.
Inside Derived
posted on 2013-08-14 14:50  紫金树下  阅读(962)  评论(0编辑  收藏  举报