实验4

#include <stdio.h>
#define N 4
int main()
{
    int a[N] = {2, 0, 2, 2};
    char b[N] = {'2', '0', '2', '2'};
    int i;
    printf("sizeof(int) = %d\n", sizeof(int));
    printf("sizeof(char) = %d\n", sizeof(char));
    printf("\n");

    for (i = 0; i < N; ++i)
    printf("%p: %d\n", &a[i], a[i]);
    printf("\n");

    for (i = 0; i < N; ++i)
    printf("%p: %c\n", &b[i], b[i]);
    printf("\n");

    printf("a = %p\n", a);
    printf("b = %p\n", b);
    return 0;
}

a，连续存放，4个。

b，连续存放，1个。

数组名a对应的值和&a[0]一样,数组名b对应的值和&b[0]一样.

 

 

TASK2

 

#include <stdio.h>
#define N 2
#define M 3
int main()
{
    int a[N][M] = {{1, 2, 3}, {4, 5, 6}};
    char b[N][M] = {{'1', '2', '3'}, {'4', '5', '6'}};
    int i, j;

    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %d\n", &a[i][j], a[i][j]);
            
    printf("\n");

    for (i = 0; i < N; ++i)
        for (j = 0; j < M; ++j)
            printf("%p: %c\n", &b[i][j], b[i][j]);
            
    return 0;
}

 

 

按行连续存放，4个

按行连续存放，1个

TASK3

#include<stdio.h>
int days_of_year(int year, int month, int day);
int main()
{
    int year, month, day;
    int days;
    while (scanf("%d%d%d", &year, &month, &day) != EOF)
    {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年中的第%d天.\n\n", year, month, day, days);
    }
    return 0;
}
int days_of_year(int year, int month, int day)
{
    int n=0;
    int i;
    int x[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
    if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
        x[1] = 29;
    for (i = 0; i < month-1; i++)
        n = n + x[i];
    return n + day;
}

 

TASK4

 

#include <stdio.h>
#define N 5
// 函数声明
void input(int x[], int n);
void output(int x[], int n);
double average(int x[], int n);
void sort(int x[], int n);
int main()
{
int scores[N];
double ave;
printf("录入%d个分数:\n", N);
input(scores, N);
printf("\n输出课程分数: \n");
output(scores, N);
printf("\n课程分数处理: 计算均分、排序...\n");
ave = average(scores, N);
sort(scores, N);
printf("\n输出课程均分: %.2f\n", ave);
printf("\n输出课程分数(高->低):\n");
output(scores, N);
return 0;
}
// 函数定义
// 输入n个整数保存到整型数组x中
void input(int x[], int n)
{
int i;
for(i=0; i<n; ++i)
scanf("%d", &x[i]);
}
// 输出整型数组x中n个元素
void output(int x[], int n)
{
int i;
for(i=0; i<n; ++i)
printf("%d ", x[i]);
printf("\n");
}
double average(int x[], int n)
{
    int i;
    double s=0;
    for(i=0;i<n;i++)
    s+=x[i];
    return s/n;
     
}
void sort(int x[],int n)
{
    int i,j,t;
    for(i=0;i<n-1;i++)
    {
       for(j=0;j<n-1-i;j++)
       {
        if(x[j]<x[j+1])
        {
            t =x[j];
            
            x[j]=x[j+1];
            
            x[j+1]=t;
            
        }
       }
    }  
}

 

TASK5

 

#include <stdio.h>
void dec2n(int x, int n); // 函数声明
int main()
{
int x;
printf("输入一个十进制整数: ");
scanf("%d", &x);
dec2n(x, 2); 
dec2n(x, 8); // 函数调用: 把x转换成八进制输出
dec2n(x, 16); // 函数调用: 把x转换成十六进制输出
return 0;
}
// 函数定义
// 功能: 把十进制数x转换成n进制，打印输出
// 补足函数实现
void dec2n(int x,int n)
{
    if(n==2)
    {
        int  i;
    int a[80];
        for(i=0;x!=0;i++)
        {
            a[i]=x%2;
            x/=2;
            
        }
        i--;
        do{
            printf("%d",a[i]);
            i--;
        }while(i>=0);
        printf("\n");
        
    }
    if(n==8)
    printf("%o\n",x);
    if(n==16)
    printf("%x",x);

}

 

TASK6

 

#include<stdio.h>

int main()
{
    int a[80][80];
    int n,i,j,k,t;
    
    printf("Enter n:");
    while(scanf("%d",&n)!=EOF)
    {
        for(i=0;i<n;i++)
        {
            for(j=i;j<n;j++)
            {
                a[i][j]=i+1;
                a[j][i]=i+1;
            } 
        }
        
        for(k=0;k<n;k++)
        {
            for(t=0;t<n;t++)
            {
                printf("%d ",a[k][t]);
            }
            
            printf("\n");
        }
        
        printf("\n");
        
        printf("Enter n:");
        
    }
    
    return 0;
}

 

TASK7

 

#include<stdio.h>
#define N 80

int main()
{
    char views1[N] = "hey, c, i hate u."; 
    char views2[N] = "hey, c, i love u.";
    
    char temp;
    int i = 0;
    printf("original views:\n");
    printf("views1: %s\n",views1);
    printf("views2: %s\n",views2);
    while(views1[i]!='\0')
    {
        temp = views1[i];
        views1[i] = views2[i];
        views2[i] = temp;
        i++;
    }
    printf("\nswapping...\n");
    printf("views1: %s\n",views1);
    printf("views2: %s\n",views2);
    
    return 0;
}

 

TASK8

 

#include <stdio.h>
#include <string.h>

#define N 5 
#define M 20

void bubble_sort(char str[][M], int n); // 函数声明

int main()
{
    char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"};
    int i;
    
    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
    printf("%s\n", name[i]);
    
    printf("\n排序中...\n");
    bubble_sort(name, N); // 函数调用
    
    printf("\n按字典序输出名单:\n");
    for (i = 0; i < N; i++) 
    printf("%s\n", name[i]);
    
    return 0;
}

void bubble_sort(char str[][M],int n)
{
    int i,j;
    char temp[M];
    for(j=0;j<n;j++)
    {
        for(i=0;i<n-1;i++)
        {
            if(strcmp(str[i],str[i+1])>0)
            {
               strcpy(temp,str[i]);
               strcpy(str[i],str[i+1]);
               strcpy(str[i+1],temp);
             }
        }
        
    }
        
}