实验5
task1_1
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#include<stdio.h>
#define N 5
void input(int x[],int n);
void output(int x[],int n);
void find_min_max(int x[],int n,int *pmin,int *pmax);
int main(){
int a[N];
int min,max;
printf("录入%d个数据：\n",N);
input(a,N);
printf("数据是：\n");
output(a,N);
printf("数据处理...\n");
find_min_max(a,N,&min,&max);
printf("输出结果:\n");
printf("min=%d,max=%d\n",min,max);
return 0;
}
void input(int x[],int n){
int i;
for(i=0;i<n;i++){
scanf("%d",&x[i]);
}
}
void output(int x[],int n){
int i;
for(i=0;i<n;i++){
printf("%d ",x[i]);
}
printf("\n");
}
void find_min_max(int x[],int n,int *pmin,int *pmax){
int i;
*pmin=*pmax=x[0];
for(i=0;i<n;i++){
if(x[i]<*pmin)
*pmin=x[i];
if(x[i]>*pmax)
*pmax=x[i];
}
}
1.找到数组中最大最小元素
2.都指向数组起始地址
task1_2
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#include<stdio.h>
#define N 5
void input(int x[],int n);
void output(int x[],int n);
int *find_max(int x[],int n);
int main(){
int a[N];
int *pmax;
printf("录入%d个数据:\n",N);
input(a,N);
printf("数据是:\n");
output(a,N);
printf("数据处理...\n");
pmax=find_max(a,N);
printf("输出结果:\n");
printf("max=%d\n",*pmax);
return 0;
}
void input(int x[],int n){
int i;
for(i=0;i<n;i++){
scanf("%d",&x[i]);
}
}
void output(int x[],int n){
int i;
for(i=0;i<n;i++){
printf("%d ",x[i]);
}
printf("\n");
}
int *find_max(int x[],int n){
int max_index=0;
int i;
for(i=0;i<n;i++){
if(x[i]>x[max_index])
max_index=i;
}
return &x[max_index];
}
1.找到数组最大元素地址并传回
2.可以
task2-1
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#include<stdio.h>
#include<string.h>
#define N 80
int main(){
char s1[N]="Learning makes me happy";
char s2[N]="Learning makes me sleepy";
char tmp[N];
printf("sizeof(s1)vs.strlen(s1):\n");
printf("sizeof(s1)=%d\n",sizeof(s1));
printf("strlen(s1)=%d\n",strlen(s1));
printf("\nbefore swap:\n");
printf("s1:%s\n",s1);
printf("s2:%s\n",s2);
printf("\nswapping...\n");
strcpy(tmp,s1);
strcpy(s1,s2);
strcpy(s2,tmp);
printf("\nafter swap:\n");
printf("s1:%s\n",s1);
printf("s2:%s\n",s2);
return 0;
}
1.80 数组总共站的空间 有效字符串长度
2.不能，s1是数组首位地址
3.是
task2-2
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#include<stdio.h>
#include<string.h>
#define N 80
int main(){
char *s1="Learning makes me happy";
char *s2="Learning makes me sleepy";
char *tmp;
printf("sizeof(s1)vs.strlen(s1):\n");
printf("sizeof(s1)=%d\n",sizeof(s1));
printf("strlen(s1)=%d\n",strlen(s1));
printf("\nbefore swap:\n");
printf("s1:%s\n",s1);
printf("s2:%s\n",s2);
printf("\nswapping...\n");
tmp=s1;
s1=s2;
s2=tmp;
printf("\nafter swap:\n");
printf("s1:%s\n",s1);
printf("s2:%s\n",s2);
return 0;
}
1.l所在地址，s1占用的内存，有效字符长度
可以，前者是字符数组名，这个是字符指针变量
task3
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#include<stdio.h>
int main(){
int x[2][4]={{1,9,8,4},{2,0,9,4}};
int i,j;
int *ptr1;
int(*ptr2)[4];
printf("输出1:使用数组名、下标直接访问二维数组元素\n");
for(i=0;i<2;i++){
for(j=0;j<4;j++)
printf("%d",x[i][j]);
printf("\n");
}
printf("\n输出2:使用指针变量ptr1(指向元素)间接访问\n");
for(ptr1=&x[0][0],i=0;ptr1<&x[0][0]+8;++ptr1,++i){
printf("%d",*ptr1);
if((i+1)%4==0)
printf("\n");
}
printf("\n输出3:使用指针变量ptr2(指向一维数组)间接访问\n");
for(ptr2=x;ptr2<x+2;++ptr2){
for(j=0;j<4;j++)
printf("%d",*(*ptr2+j));
printf("\n");
}
return 0;
}
task4
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#include<stdio.h>
#define N 80
void replace(char *str,char old_char,char new_char);
int main(){
char text[N]="Prgramming is difficult or not, it is a question.";
printf("原始文本:\n");
printf("%s\n",text);
replace(text,'i','*');
printf("处理后文本:\n");
printf("%s\n",text);
return 0;
}
void replace(char *str,char old_char,char new_char){
int i;
while(*str){
if(*str==old_char)
*str=new_char;
str++;
}
}
task5
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#include<stdio.h>
#define N 80
char *str_trunc(char *str,char x);
int main(){
char str[N];
char ch;
while(printf("输入字符串:"),gets(str)!=NULL){
printf("输入一个字符:");
ch=getchar();
printf("阶段处理...\n");
str_trunc(str,ch);
printf("阶段处理后的字符串:%s\n\n",str);
getchar();
}
return 0;
}
char *str_trunc(char *str,char x){
while(*str){
if(*str==x)
*str=0;
else str++;
}
return str;
}
task6
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#include<stdio.h>
#include<string.h>
#define N 5
int check_id(char *str);
int main(){
char *pid[N]={"31010120000721656x",
"3301061996x0203301",
"53010220051126571",
"510104199211197977",
"53010220051126133y"
};
int i;
for(i=0;i<N;++i){
if(check_id(pid[i]))
printf("%s\tTure\n",pid[i]);
else
printf("%s\tFalse\n",pid[i]);
}
return 0;
}
int check_id(char *str){
int i;
for(i=0;i<17;i++){
if(str[i]<'0'||str[i]>'9')
return 0;
}
if((str[i]<'0'||str[i]>'9')&&str[i]!='x')
return 0;
return 1;
}
task7
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#include<stdio.h>
#define N 80
void encoder(char *str,int n);
void decoder(char *str,int n);
int main(){
char words[N];
int n;
printf("输入英文文本:");
gets(words);
printf("输入n:");
scanf("%d",&n);
printf("编码后的英文文本:");
encoder(words,n);
printf("%s\n",words);
printf("对编码后的英文文本解码:");
decoder(words,n);
printf("%s\n",words);
return 0;
}
void encoder(char *str,int n){
n%=26;
while(*str){
if(*str>='a'&&*str<='z')
*str=(*str-'a'+n)%26+'a';
else if(*str>='A'&&*str<='Z')
*str=(*str-'A'+n)%26+'A';
str++;
}
}
void decoder(char *str,int n){
n%=26;
while(*str){
if(*str>='a'&&*str<='z')
*str=(*str-'a'-n+26)%26+'a';
else if(*str>='A'&&*str<='Z')
*str=(*str-'A'-n+26)%26+'A';
str++;
}
}
task8
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#include<stdio.h>
#include<string.h>
void sort(int n,char *argv[]);
int main(int argc,char *argv[]){
int i;
sort(argc-1,argv+1);
for(i=1;i<argc;i++){
printf("hello,%s\n",argv[i]);
}
return 0;
}
void sort(int n,char *argv[]){
int i,j;
char *temp;
for(i=0;i<n-1;i++){
for(j=0;j<n-1-i;j++){
if(strcmp(argv[j],argv[j+1])>0){
temp=argv[j];
argv[j]=argv[j+1];
argv[j+1]=temp;
}
}
}
}
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