实验4 8086标志寄存器及中断

任务一

task1.asm源码

assume cs:code, ds:data

data segment
   x dw 1020h, 2240h, 9522h, 5060h, 3359h, 6652h, 2530h, 7031h
   y dw 3210h, 5510h, 6066h, 5121h, 8801h, 6210h, 7119h, 3912h
data ends
code segment 
start:
    mov ax, data
    mov ds, ax
    mov si, offset x
    mov di, offset y
    call add128

    mov ah, 4ch
    int 21h

add128:
    push ax
    push cx
    push si
    push di

    sub ax, ax

    mov cx, 8
s:  mov ax, [si]
    adc ax, [di]
    mov [si], ax

    inc si
    inc si
    inc di
    inc di
    loop s

    pop di
    pop si
    pop cx
    pop ax
    ret
code ends
end start

  

line31~line34的4条inc指令,能否替换成如下代码?你的结论的依据/理由是什么?

add si, 2
add di, 2

不能。因为inc换成add有可能引起进位,导致原本计算中的adc计算错误。

 

 任务二

assume cs:code, ds:data
data segment
        str db 80 dup(?)
data ends

code segment
start:  
        mov ax, data
        mov ds, ax
        mov si, 0
s1:        
        mov ah, 1
        int 21h
        mov [si], al
        cmp al, '#'
        je next
        inc si
        jmp s1
next:
        mov ah, 2
        mov dl, 0ah
        int 21h
        
        mov cx, si
        mov si, 0
s2:     mov ah, 2
        mov dl, [si]
        int 21h
        inc si
        loop s2

        mov ah, 4ch
        int 21h
code ends
end start

  

汇编指令代码line11-18,实现的功能是?

从键盘上读取输入的字符,并保存到ds:[si],每读入一个就判断是否为#,如果是则不保存,转跳至标号next处执行;如果不是则si + 1并继续读入下一个字符。

汇编指令代码line20-22,实现的功能是?

换行。

 汇编指令代码line24-30,实现的功能是?

打印字符串,并且不会把#打出来。

任务三

assume cs:code, ds:data
data segment
	x dw 91, 792, 8536, 65521, 2021
	len equ $ - x
data ends

code segment
start:  
	mov ax, data
	mov ds, ax
	mov si, offset x
	mov cx, 5
	
s:	mov ax, [si]
	push cx
	call printNumber
	call printSpace
	add si, 2
	pop cx
	loop s
	
	mov ah, 4ch
	int 21h
	
printNumber:   
	mov dx, 0
	mov cx, 0
s1:	mov bx, 10
	div bx
	push dx
	mov dx, 0
	inc cx
	add ax, 0
	jnz s1
	
s2:	pop dx
	mov ah, 2
	add dl, '0'
	int 21h
	loop s2
	ret
	
printSpace:
	mov ah, 2
	mov dl, ' '
	int 21h
	ret

code ends
end start

  

 

任务四

1
2
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11
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21
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46
assume cs:code, ds:data
  
data segment
    str db "assembly language, it's not difficult but tedious"
    len equ $ - str
data ends
  
code segment
start:
    mov ax, data
    mov ds, ax
    mov cx, len
    mov si, 0
  
s:
    call strUpr
    inc si
    loop s
  
    mov cx, len
    mov si, 0
    mov ah, 2
  
printStr:
    mov dl, ds:[si]
    int 21h
    inc si
    loop printStr
  
    mov ah, 4ch
    int 21h
  
strUpr:
    mov al, byte ptr ds:[si]
    cmp al, 'a'
    jb back
    cmp al, 'z'
    ja back
    sub al, 20h
    mov ds:[si], al
      
back:
    ret
  
code ends
end start

  

 

任务五

assume cs:code, ds:data

data segment
    str1 db "yes", '$'
    str2 db "no", '$'
data ends

code segment
start:
    mov ax, data
    mov ds, ax

    mov ah, 1
    int 21h

    mov ah, 2
    mov bh, 0
    mov dh, 24
    mov dl, 70
    int 10h

    cmp al, '7'
    je s1
    mov ah, 9
    mov dx, offset str2
    int 21h

    jmp over

s1: mov ah, 9
    mov dx, offset str1
    int 21h
over:  
    mov ah, 4ch
    int 21h
code ends
end start

  

 

 

 该程序的功能是判断输入的字符是否为7,若为7则在屏幕的第24行70列处输出yes;若不为7则在屏幕的第24行70列处输出no。

任务六

软中断是中断的一种,软中断是由程序执行的中断 

posted @ 2021-12-13 22:36  卜文bobo  阅读(52)  评论(1)    收藏  举报