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\begin{align}\displaystyle{\left \lbrace \sum_{i=0}^n i^2 = \frac{(n^2+n)(2n+1)}{6} \right\rbrace\tag{1.2}}\end{align}
posted on 2015-10-22 17:13  bleu_crystal  阅读(108)  评论(0)    收藏  举报