Ajax后台传数组参数,接收不到报错!

 var Gid = "";
            var Name = "";
            var strGid = [];
            var strName = [];
            for (var i = 0; i < rows.length; i++) {
                Gid = rows[i]["DP001_GID"];
                Name = rows[i]["EC101_WRYMC"];
                strGid.push(Gid);
                strName.push(Name);
            }
            $.ajax({
                url: 'CuiBanSearch.ashx?Method=AcceptCuiban',
                data: { DP001_GID: strGid, EC101_WRYMC: strName },
                dataType: 'json',
                traditional: true,//数组格式转换 加上这个就可以了
                async: false,
                success: function (result) {
                }
            });

 

posted @ 2017-01-12 16:25  羁绊lov  阅读(1018)  评论(0编辑  收藏  举报