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c 数据拼接

    char buf1[] = {0x31,0x32,0x33,0x00,0x51,0x52,0x53,0xaa,0xbb,0xcc,0x00};
    int a=0xabcd6799;
    int b=0x88991122;
    int d=0x12345678;
    int c=sizeof(int)*3+sizeof(buf1);
    printf("%d\n",c);
    char *buf2=malloc(c);
    char *buf3=buf2;
    memcpy(buf2,&a,sizeof(int));
    buf2+=sizeof(int);
    memcpy(buf2,&b,sizeof(int));
    buf2+=sizeof(int);
    memcpy(buf2,buf1,sizeof(buf1));
    buf2+=sizeof(buf1);
    memcpy(buf2,&d,sizeof(int));
    
    int i=0;
    for(;i<c;i++){
        printf("0X%02X ",buf3[i]);
    }
    printf("\n");

 

posted on 2015-04-16 16:14  项羽  阅读(329)  评论(0编辑  收藏  举报