例3-11

#include<stdio.h>
int main(void)
{
    double valuel,value2;
    char op;

    printf("Type in an expression:");
    scanf_s("%lf%c%lf",&valuel,&op,&value2);
    if(op=='+')
        printf("%.2f\n",valuel+value2);
    else if(op=='-')
        printf("%.2f\n",valuel-value2);
    else if(op=='*')
        printf("%.2f\n",valuel*value2);
    else if(op=='/')
        if(value2!=0)
        printf("%.2f\n",valuel/value2);
    else
        printf("Divisor can not be 0!\n");
    else
        printf("Unkown operator!\n");

    return 0;
}

posted @ 2013-10-06 19:29  部落波萝  阅读(142)  评论(0编辑  收藏  举报