- 自己写一个划拳的change函数来调用
- 并且用字符数组来存放输入的字符
- 最重要的就是一个循环相克
- 0 1 2
- 布 石头 剪刀
- (k1+1)%3 == k2 为赢 ,反之为输,k1==k2为平
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int time_A[3];
int time_B[3];
int hand_A[3];
int hand_B[3];
char mp[3]={'B','C','J'};
int change(char c){
if(c=='B') return 0;
if(c=='C') return 1;
if(c=='J') return 2;
}
int main(){
int n;cin>>n;
while(n--){
getchar();
char x1;char x2;
scanf("%c %c",&x1,&x2);
int k1,k2;
k1=change(x1);k2=change(x2);
if((k1+1)%3==k2){
time_A[0]++;time_B[2]++;
hand_A[k1]++;
}else if(k1==k2){
time_A[1]++;time_B[1]++;
}else{
time_A[2]++;time_B[0]++;
hand_B[k2]++;
}
}
cout<<time_A[0]<<" "<<time_A[1]<<" "<<time_A[2]<<"\n";
cout<<time_B[0]<<" "<<time_B[1]<<" "<<time_B[2]<<"\n";
int max1=0,max2=0;
for(int i=1;i<3;i++){
if(hand_A[i]>hand_A[max1]) max1=i;
if(hand_B[i]>hand_B[max1]) max2=i;
}
cout<<mp[max1]<<" "<<mp[max2];
return 0;
}