二分查找

二分查找也叫折半查找必须在有序存储中查找

思路:顾名思义每次查找一半,直到找到为止

过程:先定义一个中位数,把数据分为左右两个部分,跟要找的数进行比较,小于则往左递归,大于则往右递归

由上述过程可以知道对于找到数的快慢决定点在于对于中位数的,当中位数越接近要找到的值,则查找速度越快

这里中位数的定义方法改为差值查找,对二分查找进行升级

import java.util.ArrayList;

public class BinarySearch {

    public static void main(String[] args) {
//        int arr[] = {1, 8, 10, 89, 1000, 1234};
//        int resIndex = binarySearch(arr, 0, arr.length - 1, 1);
//        System.out.println(resIndex);


//        int arr[] = {1, 8, 10, 89, 1000, 1000, 1000, 1000, 1234};
        int arr[] = {1, 2, 3, 11, 12, 13, 18, 19, 20};
        ArrayList resIndexList = binarySearch2(arr, 0, arr.length - 1, 11);
        System.out.println(resIndexList);
    }

    public static int binarySearch(int[] arr, int left, int right, int findVal) {
        if (left > right) {
            return -1;
        }
        int mid = (left + right) / 2;
        int midVal = arr[mid];
        if (findVal > midVal) {
            return binarySearch(arr, mid + 1, right, findVal);
        } else if (findVal < midVal) {
            return binarySearch(arr, left, mid - 1, findVal);
        } else {
            return mid;
        }
    }

    //二分升级
    public static ArrayList<Integer> binarySearch2(int[] arr, int left, int right, int findVal) {
        if (left > right) {
            return new ArrayList<Integer>();
        }
        int mid = left + (right - left) * (findVal - arr[left]) / (arr[right] - arr[left]);//差值查找mid
        int midVal = arr[mid];
        if (findVal > midVal) {
            return binarySearch2(arr, mid + 1, right, findVal);
        } else if (findVal < midVal) {
            return binarySearch2(arr, left, mid - 1, findVal);
        } else {
            ArrayList<Integer> resIndexlist = new ArrayList<Integer>();
            int temp = mid - 1;
            while (true) {
                if (temp < 0 || arr[temp] != findVal) {
                    break;
                }
                resIndexlist.add(temp);
                temp -= 1;//往左移动
            }
            resIndexlist.add(mid);
            temp = mid + 1;
            while (true) {
                if (temp > arr.length - 1 || arr[temp] != findVal) {
                    break;
                }
                resIndexlist.add(temp);
                temp += 1;//往右移动
            }
            return resIndexlist;
        }
    }
}
posted @ 2020-01-14 21:07  Axs  阅读(153)  评论(0)    收藏  举报