实验5
任务一:
publisher.hpp
1 #pragma once 2 3 #include <string> 4 5 // 发行/出版物类:Publisher (抽象类) 6 class Publisher { 7 public: 8 Publisher(const std::string &name_ = ""); // 构造函数 9 virtual ~Publisher() = default; 10 11 public: 12 virtual void publish() const = 0; // 纯虚函数,作为接口继承 13 virtual void use() const = 0; // 纯虚函数,作为接口继承 14 15 protected: 16 std::string name; // 发行/出版物名称 17 }; 18 19 // 图书类: Book 20 class Book: public Publisher { 21 public: 22 Book(const std::string &name_ = "", const std::string &author_ = ""); // 构造函数 23 24 public: 25 void publish() const override; // 接口 26 void use() const override; // 接口 27 28 private: 29 std::string author; // 作者 30 }; 31 32 // 电影类: Film 33 class Film: public Publisher { 34 public: 35 Film(const std::string &name_ = "", const std::string &director_ = ""); // 构造函数 36 37 public: 38 void publish() const override; // 接口 39 void use() const override; // 接口 40 41 private: 42 std::string director; // 导演 43 }; 44 45 46 // 音乐类:Music 47 class Music: public Publisher { 48 public: 49 Music(const std::string &name_ = "", const std::string &artist_ = ""); 50 51 public: 52 void publish() const override; // 接口 53 void use() const override; // 接口 54 55 private: 56 std::string artist; // 音乐艺术家名称 57 };
publisher.cpp
1 #include <iostream> 2 #include <string> 3 #include "publisher.hpp" 4 5 // Publisher类:实现 6 Publisher::Publisher(const std::string &name_): name {name_} { 7 } 8 9 10 // Book类: 实现 11 Book::Book(const std::string &name_ , const std::string &author_ ): Publisher{name_}, author{author_} { 12 } 13 14 void Book::publish() const { 15 std::cout << "Publishing book《" << name << "》 by " << author << '\n'; 16 } 17 18 void Book::use() const { 19 std::cout << "Reading book 《" << name << "》 by " << author << '\n'; 20 } 21 22 23 // Film类:实现 24 Film::Film(const std::string &name_, const std::string &director_):Publisher{name_},director{director_} { 25 } 26 27 void Film::publish() const { 28 std::cout << "Publishing film <" << name << "> directed by " << director << '\n'; 29 } 30 31 void Film::use() const { 32 std::cout << "Watching film <" << name << "> directed by " << director << '\n'; 33 } 34 35 36 // Music类:实现 37 Music::Music(const std::string &name_, const std::string &artist_): Publisher{name_}, artist{artist_} { 38 } 39 40 void Music::publish() const { 41 std::cout << "Publishing music <" << name << "> by " << artist << '\n'; 42 } 43 44 void Music::use() const { 45 std::cout << "Listening to music <" << name << "> by " << artist << '\n'; 46 }
task1.cpp
1 #include <memory> 2 #include <iostream> 3 #include <vector> 4 #include "publisher.hpp" 5 6 void test1() { 7 std::vector<Publisher *> v; 8 9 v.push_back(new Book("Harry Potter", "J.K. Rowling")); 10 v.push_back(new Film("The Godfather", "Francis Ford Coppola")); 11 v.push_back(new Music("Blowing in the wind", "Bob Dylan")); 12 13 for(Publisher *ptr: v) { 14 ptr->publish(); 15 ptr->use(); 16 std::cout << '\n'; 17 delete ptr; 18 } 19 } 20 21 //void test2() { 22 // std::vector<std::unique_ptr<Publisher>> v; 23 // 24 // v.push_back(std::make_unique<Book>("Harry Potter", "J.K. Rowling")); 25 // v.push_back(std::make_unique<Film>("The Godfather", "Francis Ford Coppola")); 26 // v.push_back(std::make_unique<Music>("Blowing in the wind", "Bob Dylan")); 27 // 28 // for(const auto &ptr: v) { 29 // ptr->publish(); 30 // ptr->use(); 31 // std::cout << '\n'; 32 // } 33 //} 34 35 void test3() { 36 Book book("A Philosophy of Software Design", "John Ousterhout"); 37 book.publish(); 38 book.use(); 39 } 40 41 int main() { 42 std::cout << "运行时多态:纯虚函数、抽象类\n"; 43 44 std::cout << "\n测试1: 使用原始指针\n"; 45 test1(); 46 47 // std::cout << "\n测试2: 使用智能指针\n"; 48 // test2(); 49 50 std::cout << "\n测试3: 直接使用类\n"; 51 test3(); 52 }
输出结果:

#问题1:抽象类机制
(1)是什么决定了 Publisher 是抽象类?用一句话说明,并指出代码中的具体依据。
含有virtual的纯虚函数;
virtual void publish() const = 0;
virtual void use() const = 0;
(2)如果在 main.cpp 里直接写 Publisher p; 能否编译通过?为什么?
不能;抽象类Publish只能定义抽象类的引用和指针,不能实例化对象
##问题2:纯虚函数与接口继承
(1) Book 、 Film 、 Music 必须实现哪两个函数才能通过编译?请写出其完整函数声明。
void publish() const override;
void use() const override;
(2) 在 publisher.cpp 的 Film 类实现中,把两个成员函数实现里的 const 去掉(保持函数体不变),重新编译,报错信息是什么?
[Error] prototype for 'void Film::publish()' dose not match any in class 'Film'
[Error] prototype for 'void Film::use()' dose not match any in class 'Film'
该函数实现没有与Film类中的成员函数匹配,类声明带const,实现也需带const
###问题3:运行时多态与虚析构
(1)在 test1() 里, for (Publisher *ptr : v) 中 ptr 的声明类型是什么?
抽象类Publisher的指针类型
(2)当循环执行到 ptr->publish(); 时, ptr 实际指向的对象类型分别有哪些?(按循环顺序写出)
Book,Film,Music
(3)基类 Publisher 的析构函数为何声明为 virtual ?若删除 virtual ,执行 delete ptr; 会出现什么问题?
确保通过基类指针删除派生类对象时,能够正确调用派生类的析构函数;
只会调用基类的析构函数,派生类的不会调用;会导致派生类的内存泄露
任务二:
book.hpp
1 #pragma once 2 #include <string> 3 4 // 图书描述信息类Book: 声明 5 class Book { 6 public: 7 Book(const std::string &name_, 8 const std::string &author_, 9 const std::string &translator_, 10 const std::string &isbn_, 11 double price_); 12 13 friend std::ostream& operator<<(std::ostream &out, const Book &book); 14 15 private: 16 std::string name; // 书名 17 std::string author; // 作者 18 std::string translator; // 译者 19 std::string isbn; // isbn号 20 double price; // 定价 21 };
book.cpp
1 #include <iomanip> 2 #include <iostream> 3 #include <string> 4 #include "book.hpp" 5 6 7 // 图书描述信息类Book: 实现 8 Book::Book(const std::string &name_, 9 const std::string &author_, 10 const std::string &translator_, 11 const std::string &isbn_, 12 double price_):name{name_}, author{author_}, translator{translator_}, isbn{isbn_}, price{price_} { 13 } 14 15 // 运算符<<重载实现 16 std::ostream& operator<<(std::ostream &out, const Book &book) { 17 using std::left; 18 using std::setw; 19 20 out << left; 21 out << setw(15) << "书名:" << book.name << '\n' 22 << setw(15) << "作者:" << book.author << '\n' 23 << setw(15) << "译者:" << book.translator << '\n' 24 << setw(15) << "ISBN:" << book.isbn << '\n' 25 << setw(15) << "定价:" << book.price; 26 27 return out; 28 }
booksale.hpp
1 #pragma once 2 3 #include <string> 4 #include "book.hpp" 5 6 // 图书销售记录类BookSales:声明 7 class BookSale { 8 public: 9 BookSale(const Book &rb_, double sales_price_, int sales_amount_); 10 int get_amount() const; // 返回销售数量 11 double get_revenue() const; // 返回营收 12 13 friend std::ostream& operator<<(std::ostream &out, const BookSale &item); 14 15 private: 16 Book rb; 17 double sales_price; // 售价 18 int sales_amount; // 销售数量 19 };
booksale.cpp
1 #include <iomanip> 2 #include <iostream> 3 #include <string> 4 #include "booksale.hpp" 5 6 // 图书销售记录类BookSales:实现 7 BookSale::BookSale(const Book &rb_, 8 double sales_price_, 9 int sales_amount_): rb{rb_}, sales_price{sales_price_}, sales_amount{sales_amount_} { 10 } 11 12 int BookSale::get_amount() const { 13 return sales_amount; 14 } 15 16 double BookSale::get_revenue() const { 17 return sales_amount * sales_price; 18 } 19 20 // 运算符<<重载实现 21 std::ostream& operator<<(std::ostream &out, const BookSale &item) { 22 using std::left; 23 using std::setw; 24 25 out << left; 26 out << item.rb << '\n' 27 << setw(15) << "售价:" << item.sales_price << '\n' 28 << setw(15) << "销售数量:" << item.sales_amount << '\n' 29 << setw(15) << "营收:" << item.get_revenue(); 30 31 return out; 32 }
task2.cpp
1 #include <algorithm> 2 #include <iomanip> 3 #include <iostream> 4 #include <string> 5 #include <vector> 6 #include "booksale.hpp" 7 8 // 按图书销售数量比较 9 bool compare_by_amount(const BookSale &x1, const BookSale &x2) { 10 return x1.get_amount() > x2.get_amount(); 11 } 12 13 void test() { 14 using std::cin; 15 using std::cout; 16 using std::getline; 17 using std::sort; 18 using std::string; 19 using std::vector; 20 using std::ws; 21 22 vector<BookSale> sales_records; // 图书销售记录表 23 24 int books_number; 25 cout << "录入图书数量: "; 26 cin >> books_number; 27 28 cout << "录入图书销售记录\n"; 29 for(int i = 0; i < books_number; ++i) { 30 string name, author, translator, isbn; 31 double price; 32 cout << string(20, '-') << "第" << i+1 << "本图书信息录入" << string(20, '-') << '\n'; 33 cout << "录入书名: "; getline(cin>>ws, name); 34 cout << "录入作者: "; getline(cin>>ws, author); 35 cout << "录入译者: "; getline(cin>>ws, translator); 36 cout << "录入isbn: "; getline(cin>>ws, isbn); 37 cout << "录入定价: "; cin >> price; 38 39 Book book(name, author, translator, isbn, price); 40 41 double sales_price; 42 int sales_amount; 43 44 cout << "录入售价: "; cin >> sales_price; 45 cout << "录入销售数量: "; cin >> sales_amount; 46 47 BookSale record(book, sales_price, sales_amount); 48 sales_records.push_back(record); 49 } 50 51 // 按销售册数排序 52 sort(sales_records.begin(), sales_records.end(), compare_by_amount); 53 54 // 按销售册数降序输出图书销售信息 55 cout << string(20, '=') << "图书销售统计" << string(20, '=') << '\n'; 56 for(auto &record: sales_records) { 57 cout << record << '\n'; 58 cout << string(40, '-') << '\n'; 59 } 60 } 61 62 int main() { 63 test(); 64 }
输出结果:

#问题1:重载运算符<<
(1)找出运算符 << 被重载了几处?分别用于什么类型?
2处;
Book类重载:std::ostream& operator<<(std::ostream &out,const Book &book)
BookSale类重载:std::ostream& operator<<(std::ostream &out,const BookSale &item)
(2)找出使用重载 << 输出对象的代码,写在下面。
cout << record << '\n';
##问题2:图书销售统计
(1)图书销售记录"按销售数量降序排序",代码是如何实现的?
通过函数
bool compare_by_amount(const BookSale &x1, const BookSale &x2) {
return x1.get_amount() > x2.get_amount();
}
和
sort(sales_records.begin(), sales_records.end(), compare_by_amount);
实现
若x1的销售数量大于x2,则返回true,sort降序排列;
否则返回false,sort升序排列
(2)拓展(选答*):如果使用lambda表达式,如何实现"按销售数量降序排序"?
sort(sales_records.begin(),sales_records.end(),[](const BookSale &x1,const BookSale &x2) { return x1.get_amount() > x2.get_amount() } );
任务四:
pet.hpp
1 #pragma once 2 3 #include<iostream> 4 #include<string> 5 6 class MachinePet { 7 public: 8 MachinePet(const std::string& name); 9 virtual ~MachinePet() = default; 10 11 virtual std::string get_nickname() const = 0; 12 virtual std::string talk() const = 0; 13 protected: 14 std::string nickname; 15 }; 16 17 class PetCat:public MachinePet { 18 public: 19 PetCat(const std::string& name); 20 21 std::string get_nickname() const override; 22 std::string talk() const override; 23 }; 24 25 class PetDog:public MachinePet { 26 public: 27 PetDog(const std::string& name); 28 29 std::string get_nickname() const override; 30 std::string talk() const override; 31 };
pet.cpp
1 #include"pet.hpp" 2 3 #include<iostream> 4 #include<string> 5 6 MachinePet::MachinePet(const std::string& name):nickname{name} {} 7 8 PetCat::PetCat(const std::string& name):MachinePet{name} {} 9 10 std::string PetCat::get_nickname() const { 11 return MachinePet::nickname; 12 } 13 14 std::string PetCat::talk() const { 15 return "miao wu~"; 16 } 17 18 PetDog::PetDog(const std::string& name):MachinePet{name} {} 19 20 std::string PetDog::get_nickname() const { 21 return MachinePet::nickname; 22 } 23 24 std::string PetDog::talk() const { 25 return "wang wang~"; 26 }
task4.cpp
1 #include <iostream> 2 #include <memory> 3 #include <vector> 4 #include "pet.hpp" 5 6 void test1() { 7 std::vector<MachinePet *> pets; 8 9 pets.push_back(new PetCat("miku")); 10 pets.push_back(new PetDog("da huang")); 11 12 for(MachinePet *ptr: pets) { 13 std::cout << ptr->get_nickname() << " says " << ptr->talk() << '\n'; 14 delete ptr; // 须手动释放资源 15 } 16 } 17 18 //void test2() { 19 // std::vector<std::unique_ptr<MachinePet>> pets; 20 // 21 // pets.push_back(std::make_unique<PetCat>("miku")); 22 // pets.push_back(std::make_unique<PetDog>("da huang")); 23 // 24 // for(auto const &ptr: pets) 25 // std::cout << ptr->get_nickname() << " says " << ptr->talk() << '\n'; 26 //} 27 28 void test3() { 29 // MachinePet pet("little cutie"); // 编译报错:无法定义抽象类对象 30 31 const PetCat cat("miku"); 32 std::cout << cat.get_nickname() << " says " << cat.talk() << '\n'; 33 34 const PetDog dog("da huang"); 35 std::cout << dog.get_nickname() << " says " << dog.talk() << '\n'; 36 } 37 38 int main() { 39 std::cout << "测试1: 使用原始指针\n"; 40 test1(); 41 42 // std::cout << "\n测试2: 使用智能指针\n"; 43 // test2(); 44 45 std::cout << "\n测试3: 直接使用类\n"; 46 test3(); 47 }
输出结果:

任务五:
complex.hpp
1 #pragma once 2 3 #include<iostream> 4 5 template<typename T> 6 class Complex { 7 public: 8 Complex(T real_ = 0,T image_ = 0); 9 Complex& operator+=(const Complex &c); 10 bool operator==(const Complex &c) const; 11 12 T get_real() const; 13 T get_imag() const; 14 15 16 friend Complex operator+(const Complex &c1,const Complex &c2) { 17 return Complex(c1.real + c2.real,c1.image + c2.image); 18 } 19 20 friend std::ostream& operator<<(std::ostream &out,const Complex &c) { 21 if(c.image >= 0) 22 out << c.real << " + " << c.image << "i"; 23 else 24 out << c.real << " - " << -c.image << "i"; 25 26 return out; 27 } 28 29 friend std::istream& operator>>(std::istream &in,Complex &c) { 30 in >> c.real >> c.image; 31 return in; 32 } 33 34 private: 35 T real, image; 36 }; 37 38 template<typename T> 39 Complex<T>::Complex(T real_,T image_):real{real_},image{image_} {} 40 41 template<typename T> 42 Complex<T>& Complex<T>::operator+=(const Complex<T> &c) { 43 real += c.real; 44 image += c.image; 45 46 return *this; 47 } 48 49 template<typename T> 50 bool Complex<T>::operator==(const Complex<T> &c) const { 51 if(real == c.real && image == c.image) 52 return true; 53 else 54 return false; 55 } 56 57 template<typename T> 58 T Complex<T>::get_real() const { 59 return real; 60 } 61 62 template<typename T> 63 T Complex<T>::get_imag() const { 64 return image; 65 }
task5.cpp
1 #include <iostream> 2 #include "Complex.hpp" 3 4 void test1() { 5 using std::cout; 6 using std::boolalpha; 7 8 Complex<int> c1(2, -5), c2(c1); 9 10 cout << "c1 = " << c1 << '\n'; 11 cout << "c2 = " << c2 << '\n'; 12 cout << "c1 + c2 = " << c1 + c2 << '\n'; 13 14 c1 += c2; 15 cout << "c1 = " << c1 << '\n'; 16 cout << boolalpha << (c1 == c2) << '\n'; 17 } 18 19 void test2() { 20 using std::cin; 21 using std::cout; 22 23 Complex<double> c1, c2; 24 cout << "Enter c1 and c2: "; 25 cin >> c1 >> c2; 26 cout << "c1 = " << c1 << '\n'; 27 cout << "c2 = " << c2 << '\n'; 28 29 const Complex<double> c3(c1); 30 cout << "c3.real = " << c3.get_real() << '\n'; 31 cout << "c3.imag = " << c3.get_imag() << '\n'; 32 } 33 34 int main() { 35 std::cout << "自定义类模板Complex测试1: \n"; 36 test1(); 37 38 std::cout << "\n自定义类模板Complex测试2: \n"; 39 test2(); 40 }
输出结果:

实验总结
通过这次实验,我对抽象类与纯虚函数更加熟练,了解了抽象类至少包含一个纯虚函数(= 0),了解了虚析构函数确保派生类对象被正确销毁,防止内存泄漏的重要作用;
对模板类,友元函数与运算符重载有了更深的认识。
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