实验五

实验任务1

task1_1.

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
    char name[M];
    char author[M];
 } Book;
 
 int main()
 {
     Book x[N]={ {"一九八四","乔治.奥威尔"},
                {"美丽新世界","赫胥黎" },
                {"昨日的世界","史蒂芬.茨威格" },
                {"万历十五年","黄仁宇"},
                {"一只特立独行的猪","王小波"} 
              };
int i;

FILE *fp;
 
 fp=fopen("data1.txt","w");
 
 if(fp==NULL)
 {
     printf("fail to open file\n");
     return 1;
 }
 
 for(i=0;i<N;++i)
 {
     fprintf(fp,"%-20s %-20s\n",x[i].name,x[i].author);
     printf("%-20s %-20s\n",x[i].name,x[i].author);
 }
 fclose(fp);

task1_2.

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
    char name[M];
    char author[M];
 } Book;
 
 int main()
 {
     Book x[N];
    int i;

FILE *fp;
 
 fp=fopen("data1.txt","r");
 
 if(fp==NULL)
 {
     printf("fail to open file\n");
     return 1;
 }
 
 for(i=0;i<N;++i)
 {
     fscanf(fp,"%s %s\n",x[i].name,x[i].author);
     printf("%s %s\n",x[i].name,x[i].author);
 }
 fclose(fp);
 
 return 0;
}

实验任务2

task2_1.

#include <stdio.h>
#define N 5
#define M 80

typedef struct
{
    char name[M];
    char author[M];
 } Book;
 
 int main()
 {
     Book x[N]={ {"一九八四","乔治.奥威尔"},
                {"美丽新世界","赫胥黎" },
                {"昨日的世界","史蒂芬.茨威格" },
                {"万历十五年","黄仁宇"},
                {"一只特立独行的猪","王小波"} 
              };
int i;

FILE *fp;
 
 fp=fopen("data2.dat","wb");
 
 if(fp==NULL)
 {
     printf("fail to open file\n");
     return 1;
 }
 
 fwrite(x,sizeof(Book),N,fp);
 
 fclose(fp);
 
 return 0;
}

task2_2.

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M]; 
char author[M]; 
}Book;
int main()
{
Book x[N];
int i;
FILE *fp;

fp = fopen("data2.dat", "rb");

if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}

fread(x, sizeof(Book), N, fp);

for(i=0; i<N; ++i)

printf("%-20s%-20s\n", x[i].name, x[i].author);

fclose(fp);

return 0;
}

实验任务3

task3_1.

#include <stdio.h>
int main()
{
FILE *fin, *fout;
char ch;

fin = fopen("data3_1.txt", "r");

if(fin == NULL)
{
printf("fail to open data3_1.txt\n");
return 1;
}

fout = fopen("data3_2.txt", "w");

if(fout == NULL)

{
printf("fail to open data3_2.txt\n");
return 1;
}

while( !feof(fin) )
{
ch = fgetc(fin);

if(ch >= 'a' && ch <= 'z')
ch -= 32;

fputc(ch, fout);
}

fclose(fin);
fclose(fout);

return 0;
}

task3_2.

#include <stdio.h>
int main()
{
    int i=0;
    FILE*fp;
    char ch;
    fp=fopen("data3_1.txt","x");
    if(fp==NULL)
    {
        printf("fail to find file\n");
        return  1;
    }
    while ((ch=fgetc(fp))!=EOF)
    {
        if(ch!='\n'&&ch!=' '&&ch!='\t')
        i++;
    }
    printf("data3_1.txt中共包含字符数：%d",i);
    
    fclose(fp);
    
    return 0;
}

实验任务4

task4.

typedef struct
{
long no;
char name[20];
int score;
} STU;

int findMinlist(STU s[], int n, STU t[]);

int main()
{
STU stu[N], minlist[N];
int count, i;
FILE *fin, *fout;

fin = fopen("data4_1.txt", "r");

if(fin == NULL)
{
printf("fail to open file\n");

 return 1;
}
for(i=0; i<N; ++i)
{
fscanf(fin, "%ld %s %d", &stu[i].no, stu[i].name, &stu[i].score);
printf("%ld %s %d\n", stu[i].no, stu[i].name, stu[i].score);
}
fclose(fin);

count = findMinlist(stu, N, minlist);

printf("\n一共有%d个最低分，信息如下: \n", count);
for(i=0; i<count; ++i)
printf("%ld %s %d\n", minlist[i].no, minlist[i].name,
minlist[i].score);

fout = fopen("data4_2.txt", "w");
if(fout == NULL)
{
printf("fail to open file\n");
return 1;
}
for(i=0; i<count; ++i)
fprintf(fout, "%ld %s %d\n", minlist[i].no, minlist[i].name,
minlist[i].score);
fclose(fout);
return 0;
}
int findMinlist(STU s[], int n, STU t[])
{
int i, k, min_score;

min_score = s[0].score;
for(i=1; i<n; ++i)
if(s[i].score < min_score)
min_score = s[i].score;
k = 0;
for(i=0; i<n; ++i)
if(s[i].score == min_score)
{
t[k] = s[i];
++k;
}
return k;
}

实验任务5

task5.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define N 10

typedef struct
{
     long int id;
     char name[20];
     float objective; 
     float subjective; 
     float sum;
     char level[10];
} STU;


void input(STU s[], int n);
void output(STU s[], int n);
void process(STU s[], int n);

int main()
{
     STU stu[N];
     
     printf("从文件读入%d个考生信息: 准考证号，姓名，客观题得分(<=40)，操作题得分(<=60)\n", N);
     input(stu, N);
     
     printf("\n对考生信息进行处理: 计算总分，确定等级\n");
     process(stu, N);
     
     printf("\n打印考生完整信息, 并保存到文件中");
     output(stu, N);

  return 0;
}

void input(STU s[], int n)
{
     int i;
     FILE *fin;
     fin = fopen("examinee.txt", "r");
     if (fin == NULL)
     {
         printf("fail to open file\n");
         exit(0);
     }
     
     while (!feof(fin))
     {
         for (i = 0; i < n; i++)
         fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name,&s[i].objective, &s[i].subjective);
     }
   fclose(fin);
}


void output(STU s[], int n)
{
   FILE *fout;
   int i;
   printf("\n");
   printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
   for (i = 0; i < n; i++)
   printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
   
   fout = fopen("result.txt", "w");
   if (!fout)
   {
       printf("fail to open or create result.txt\n");
       exit(0);
    }
    
    fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
    for (i = 0; i < n; i++)
       fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
  fclose(fout);
}


void process(STU s[], int n)
{
     int i,j;
     STU t;
     for(i=0;i<n;i++)
     {
         s[i].sum=(s[i].objective)+(s[i].subjective);
     }
     for(j=0;j<n-1;j++)
     for(i=0;i<n-j-1;i++)
     {
         if(s[i].sum<s[i+1].sum)
          {
          t=s[i];
         s[i]=s[i+1];
         s[i+1]=t;
    }
     }
     for(i=0;i<1;i++)
     {
         strcpy(s[i].level,"优秀");
     }
     for(;i>=i&&i<5;i++)
     strcpy(s[i].level,"合格");
     for(;i<n;i++)
     {
         strcpy(s[i].level,"不合格");
     }
}

实验任务6

task6.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 80
#define M 5

typedef struct
{
   long int id; 
   char name[20];
   char banji[60];
}STU;
int main()
{
    int i,j; 
    STU x[N],ran[M];
    FILE *fin,*fout;
    fin = fopen("list.txt","r");
    
    if(fin == NULL) 
    { 
       printf("fail to open list.txt\n"); 
       return 1;
       }
       
    for(i=0;i<N;i++)
    {
       fscanf(fin, "%ld %s %s", &x[i].id, x[i].name, x[i].banji); 
    }
    
    fclose(fin);
    
    srand(time(0));   
    j = rand()%(80)+1;   
    
    for(i=0;i<M;i++)
    {
        ran[i] = x[j];
        j = rand()%(80)+1;
    }
    
    fout = fopen("lucky.txt", "w"); 
    
    if(fout == NULL) 
    { 
       printf("fail to open file\n"); 
       return 1; 
       }
    
    for(i=0;i<M;i++) 
    {
       fprintf(fout, "%ld %s %s\n", ran[i].id, ran[i].name, ran[i].banji); 
       printf("%ld %s %s\n", ran[i].id, ran[i].name, ran[i].banji);
    }
    
    fclose(fout); 
    
    return 0;
}

posted @ 2022-06-07 12:49 Ares-Snape 阅读(13) 评论(1) 收藏举报

刷新页面返回顶部

实验五

公告