Marshal's confusion II
Time Limit: 1000 MS Memory Limit: 65536 K
Total Submit: 239(80 users) Total Accepted: 73(66 users) Rating: Special Judge: No
Description
one day, Marshal want to show the answer :Calculate S(n). S(n)=1^3+2^3 +3^3 +......+n^3 .
Input
Each line will contain one integer N(1 < n < 1000000000). Process to end of file.
Output
For each case, output the last four dights of S(N) in one line.
Sample Input
1 2
Sample Output
0001 0009 
#include<cmath>
#include<queue>
#include<iostream>
using namespace std;
const int m=10000;
typedef long LL;
int main()
{
    LL n;
    while(~scanf("%ld",&n))//1^3+2^3+...+n^3=[n(n+1)/2]^2
    {
        LL a;
        a=n*(n+1)/2%m;
        LL sum=a*a%m;
        printf("%04d\n",sum);
    }
    return 0;
}