一道经典的C++题,关于分钱的问题,适合新手阅读(黑客X档案论坛题目) [c#]

 前几天CSDN论坛的首页,看到一则帖子,题目是:“一道经典的C++题,关于分钱的问题,适合新手阅读(黑客X档案论坛题目) ”,链接如下:http://blog.csdn.net/gisfarmer/archive/2009/02/08/3869236.aspx

题如下:
把一张面值为一元的纸币,换成一分,二分,五分的硬币,共有多少种换法?编程输出每一种不同的算法。

这道题很简单,是最简单的C++题,用C也可以做。

 

看了原贴http://bbs.hackerxfiles.net/thread-98055-15-1.htmlhttp://blog.csdn.net/gisfarmer/archive/2009/02/08/3869236.aspx

里面有很多答案,说实在的,有点看不下去了,因为总感受写的代码有点别扭,做的一些循环都像是写死了的。。

比如:

  1. int x=0,y=0,z=0,n=0;   
  2.      int count=0;   
  3.   
  4.      for(z=1;z<20;z++)   
  5.      {   
  6.           for(y=1;y<=(100-z*5)/2;y++)   

我不知道z<20为什么要这么写,为什么是20呢?

还有就是如果如果再加一个一毛,或者是五毛,求共有多少种换法,这又怎么写呢?

又或者是分的不是一块钱,分的是五块钱,求共有多少种换法,又怎么写呢?

。。。哎,我也是写程序的,很怕业务的改变,所以在想,能不能写一个通用点的方法,于是自己写了一个如下,还请路过的指教一下(本人是菜鸟).

写了两个方法,一个需要输出明细,一个不需要输出明细,大家可以试着玩一下。。

 

c#:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleStudy
{
    class SumNumberDemo
    {
        static void Main() {

            Console.WriteLine("SumNumberDemo");
            List<int> intList = new List<int>();
            string reString =string.Empty;
            int count = 0;
            intList.Add(1);
            intList.Add(2);
            intList.Add(5);
            //intList.Add(7);
            //intList.Add(9);
            //不需要输出明细
            SplitMoney(100, 0, intList, 0, ref count);
            //输出明细
            //SplitMoney(10, 0, intList, 0, reString, ref count);
            Console.WriteLine(string.Format("总共有{0}种分法",count));
        }

        /// <summary>
        /// 分钱方法
        /// </summary>
        /// <param name="pmMoney">被分的钱</param>
        /// <param name="pmMoneyNow">当前分法的钱的和</param>
        /// <param name="pmMoneyList">分钱列表</param>
        /// <param name="pmMoneyIndex">当前分钱索引</param>
        /// <param name="pmString">当前分法明细</param>
        /// <param name="pmSplitCount">分钱方法总数统计</param>
        static void SplitMoney(int pmMoney, int pmMoneyNow, List<int> pmMoneyList, int pmMoneyIndex, string pmString, ref int pmSplitCount)
        {
            int snCount=pmMoneyList.Count;

            if (pmMoneyIndex < pmMoneyList.Count)
            {
                for (int i = 0; i * pmMoneyList[pmMoneyIndex] <= pmMoney; i++)
                {
                    //当前和统计
                    int snSumNow = i * pmMoneyList[pmMoneyIndex]+pmMoneyNow;

                    //--begin----这个字符串主要是为了输出的,如果不要求输出可以注释掉----------------
                    string snString = string.Empty;
                    if (string.IsNullOrEmpty(pmString))
                    {
                        snString = string.Format("{0}*{1}",i, pmMoneyList[pmMoneyIndex]);
                    }
                    else {
                        snString = string.Format("{0}+{1}*{2}", pmString, i, pmMoneyList[pmMoneyIndex]);
                    }
                    //---end------------------

                    if (snSumNow == pmMoney)
                    {
                        //------begin-------------
                        for (int j = pmMoneyIndex+1; j < snCount;j++ )
                        {
                            snString += string.Format("+0*{0}", pmMoneyList[j]);
                        }
                        //-------end-------------
                        pmSplitCount++;

                        Console.WriteLine(string.Format("---{0}={1}---",snString,pmMoney));
                    }
                    else
                    {
                        SplitMoney(pmMoney, snSumNow, pmMoneyList, pmMoneyIndex + 1, snString, ref pmSplitCount);
                    }

                }
            }

        }

        /// <summary>
        /// 分钱方法
        /// </summary>
        /// <param name="pmMoney">被分的钱</param>
        /// <param name="pmNoneyNow">当前分法的钱的和</param>
        /// <param name="pmMoneyList">分钱列表</param>
        /// <param name="pmMoneyIndex">当前分钱索引</param>
        /// <param name="pmSplitCount">分钱方法总数统计</param>
        static void SplitMoney(int pmMoney, int pmNoneyNow, List<int> pmMoneyList, int pmMoneyIndex, ref int pmSplitCount)
        {
            int snCount = pmMoneyList.Count;
           
            if (pmMoneyIndex < pmMoneyList.Count)
            {
                for (int i = 0; i * pmMoneyList[pmMoneyIndex] <= pmMoney; i++)
                {
                    //当前和统计
                    int snSumNow = i * pmMoneyList[pmMoneyIndex] + pmNoneyNow;
                    if (snSumNow == pmMoney)
                    {
                        pmSplitCount++;
                    }
                    else
                    {
                        SplitMoney(pmMoney, snSumNow, pmMoneyList, pmMoneyIndex + 1, ref pmSplitCount);
                    }
                }
            }

        }
    }
}

 

posted @ 2009-02-10 12:45  极品菜鸟  阅读(2129)  评论(5编辑  收藏  举报