Python实现冒泡排序

方法1:
L1 = [4,1,7,8,9,2,3]
for i in range(len(L1)-1):
    for j in range(0,len(L1)-1-i):
         if L1[j] > L1[j+1]:
             L1[j],L1[j+1] = L1[j+1],L1[j]

print(L1)

方法2:
L1 = [4,1,7,8,9,2,3]
for i in range(len(L1) - 1):
    for j in range(i+1, len(L1)):
        if L1[i] > L1[j]:
            L1[i], L1[j] = L1[j], L1[i]
            print(L1)

print(L1)

posted @ 2021-09-11 23:33  Peter_Yi  阅读(57)  评论(0)    收藏  举报