BUUCTF-RE-babymips

[UTCTF2020]babymips

傻逼题。。

ghidra反编译的:

 

 就是个简单异或,但是这是错的。

根据这个ctf比赛的格式,推出:

a=[0x62,0x6c,0x7f,0x76,0x7a,0x7b,0x66,0x73,0x76,0x50,0x52,0x7d,0x40,0x54,0x55,0x79,0x40,0x49,0x47,0x4d,0x74,0x19,0x7b,0x6a,0x42,0x0a,0x4f,0x52,0x7d,0x69,0x4f,0x53,0x0c,0x64,0x10,0x0f,0x1e,0x4a,0x67,0x03,0x7c,0x67,0x02,0x6a,0x31,0x67,0x61,0x37,0x7a,0x62,0x2c,0x2c,0x0f,0x6e,0x17,0x00,0x16,0x0f,0x16,0x0a,0x6d,0x62,0x73,0x25,0x39,0x76,0x2e,0x1c,0x63,0x78,0x2b,0x74,0x32,0x16,0x20,0x22,0x44,0x19,0x00,0x00,0x00,0x00,0x00,0x4e]
for i in range(len(a)):
    print(chr(a[i]^(i+0x17)),end='')

然后跑出来是这样的:

utflag{mips_cpp_gang_5VDm:~`N]ze;\)5%vZ=C'C(r#$q=*efD"ZNY_GX>6&sn.wF8$v*mvA@'}efghi$

本来以为只有前几位是对的

结果一交,交上了???

posted @ 2020-08-07 20:18  Basstorm  阅读(354)  评论(0编辑  收藏  举报