Swift - 复杂数据类型说明(数组,字典,结构体,枚举)
一、数组 - Array
var types = ["none","warning","error"]//省略类型的数组声明
var menbers = [String]()//声明一个空数组
menbers.append("six") //添加元素
menbers += ["seven"] //添加元素
menbers.insert("one", at: 0)//指定位置添加元素
menbers[0] = "message" //通过下标修改数组中的数据
menbers[0...2] = ["message","hangge","com"] //通过小标区间替换数据(前3个数据)
menbers.count // 获取数组元素个数
menbers.isEmpty //判断数组是否为空
//交换元素位置(第2个和第3个元素位置进行交换)
menbers.swapAt(1, 2)
menbers.remove(at: 2)//删除下标为2的数组
menbers.removeLast()//删除最后一个元素
menbers.removeAll(keepingCapacity: true)//删除数组中所有元素
let addStringArr = types + menbers//数组组合
//使用for in 实现数组遍历
for value in menbers{
print("\(value)")
}
//通过enumerate函数同时遍历数组的所有索引与数据
for(index,value) in menbers.enumerated(){
print("索引:\(index) 数据:\(value)");
}
//过滤数组元素
let newTypes = types.filter { $0.count < 6 } //["none", "error"]
二、字典 - Dictionary(即键值对)
var empty = [String:Int]() //建立个空字典
var myDic = ["name":"hangge","url":"hangge.com"]//声明一个字典
myDic["address"] = "china"//添加或修改key值
myDic.removeValue(forKey: "name")//删除“name”这个key值
myDic["name"] = nil //同样可以删除“name”这个key值
myDic.keys //访问字典的key集合
// print(myDic.values) //访问字典的values集合
//遍历字典
for(key,value) in myDic{
print("\(key):\(value)");
}
//只遍历字典的键(key)
for key in myDic.keys{
print("\(key)");
}
//只遍历字典的值(value)
for value in myDic.values{
print("\(value)");
}
2,其它几种创建字典的方法
(1)通过元组创建字典
let tupleArray = [("Monday",30),("Tuesday",25),("Wednesday",27)]
let dictionary = Dictionary(uniqueKeysWithValues: tupleArray)
print(dictionary)
(2)通过键值序列创建字典
let names = ["Apple", "Pear"]
let prices = [7, 6]
let dict = Dictionary(uniqueKeysWithValues: zip(names, prices))
print(dict);
(3)只有键序列、或者值序列创建字典
let array = ["Monday","Tuesday","Wednesday"]
let dict1 = Dictionary(uniqueKeysWithValues:zip(1..., array))
let dict2 = Dictionary(uniqueKeysWithValues:zip(array, 1...))
print("dict1:\(dict1)")
print("dict2:\(dict2)")
(4)字典分组(比如下面生成一个以首字母分组的字典)
let names = ["Apple","Pear","Grape","Peach"]
let dict = Dictionary(grouping:names){ $0.first!}
print(dict)
3,重复键的处理
(1)zip配合速记+可以用来解决重复键的问题(相同的键值相加)
let array = ["Apple","Pear","Pear","Orange"]
let dic = Dictionary(zip(array, repeatElement(1, count: array.count)),uniquingKeysWith: +)
print(dic)
(2)下面使用元组创建字典时,遇到相同的键则取较小的那个值
let duplicatesArray = [("Monday",30),("Tuesday",25),("Wednesday",27),("Monday",28)]
let dic = Dictionary(duplicatesArray, uniquingKeysWith:min)
print(dic) // ["Monday": 28, "Tuesday": 25, "Wednesday": 27]
4,字典合并
想要将一些序列、或者字典合并到现有的字典中,可以借助如下两个合并方法:
- merge(_: uniquingKeysWith:):这种方法会修改原始Dictionary
- merging(_: uniquingKeysWith:):这种方法会创建并返回一个全新的Dictionary
var dic = ["one":10,"two":20]
//merge方法合并
let tuples = [("one",5), ("three",30)]
dic.merge(tuples, uniquingKeysWith: min)
print(dic);//["one": 5, "three": 30, "two": 20]
//merging 方法合并
let dic2 = ["one":0,"four":40]
let dic3 = dic.merging(dic2, uniquingKeysWith: min)
print(dic3)//["three": 30, "four": 40, "one": 0, "two": 20]
5,默认值
(1)过去我们如果希望当某个字典值不否存在时,使用一个指定的默认值,这个通常会使用if let来判断实现。
let dic = ["apple":1,"banana":2]
var orange:Int
if let value = dic["orange"]{
orange = value
}else{
orange = 0
}
print(orange)//打印0
(2)到了 Swift4,我们可以直接指定一个默认值,如果不存在该键值时名,会直接返回这个值。下面代码的效果同上面是一样的。
let dic = ["aaple":1,"banana":2]
let orange = dic["orange", default:0]
print(orange)//打印0
(3)下面是统计一个字符串中所有单词出现的次数。可以看到了有了默认值,实现起来会简单许多。
let str = "apple banana orange apple banana"
var wordsCount: [String: Int] = [:]
for word in str.split(separator:" "){
wordsCount["\(word)", default:0] += 1
}
print(wordsCount)//["apple": 2, "orange": 1, "banana": 2]
三、结构体 - struct
struct BookInfo {
var ID:Int = 0
var Name:String = "Defaut"
var Author:String = "Defaut"
}
var book1:BookInfo//默认构造器创建结构体实现
var book2 = BookInfo(ID: 0021, Name: "白白", Author: "baibai")//调用逐一构造器创建实列
book2.ID = 1234 //修改内部值
四、枚举 - enum
enum CompassPoint{
case north
case south
case east
case west
}
enum Planet:Int{
case mercury = 1
case venus = 2
case earth = 3
}
enum Direction{
case up
case down
func description() -> String {
switch self {
case .up:
return "向上"
case .down:
return "向下"
}
}
}
var dirctionToHead = CompassPoint.west
let earthsOrder = Planet.earth.rawValue //rawValue来获取他的原始值:3
let possiblePlanet = Planet(rawValue: 2) //通过原始值来寻找所对应的枚举成员:Venus
print(dirctionToHead)
print(earthsOrder)
print(possiblePlanet)
print(Direction.up.description())

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