随笔分类 -  莫比乌斯反演

51nod 1355 斐波那契的最小公倍数
摘要：Description 斐波那契数列定义如下： $$ f[n]= \begin{cases} 1 , & \text {if $n$ is equal to $0$ or $1$} \\ f(n 1) + f(n 2), & \text{otherwise} \end{cases} $$ 给出 $n 阅读全文
posted @ 2018-10-12 20:20 aziint 阅读(284) 评论(0) 推荐(0)

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