leetcode--Search in Rotated Sorted Array II

Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.

public class Solution {
    public boolean search(int[] A, int target) {
		boolean isIn = false;
		int index = findMin(A);		
		if(index == 0)
			isIn = (Arrays.binarySearch(A, 0, A.length, target) >= 0);
		else
			isIn = (Arrays.binarySearch(A, 0, index, target) >= 0) 
					|| (Arrays.binarySearch(A, index, A.length, target) >= 0);
		return isIn;
	}
	public static int findMin(int[] A){
		int i = A.length - 1;
		for(; i > 0; --i){
			if(A[i] < A[i - 1])
				break;
		}
		return i;
    }
}

  

posted @ 2014-06-07 11:05  Averill Zheng  阅读(116)  评论(0编辑  收藏  举报