Adjoint Matrix

 

https://en.wikipedia.org/wiki/Adjugate_matrix

 

In linear algebra, the adjugateclassical adjoint, or adjunct of a square matrix is the transpose of its cofactor matrix.[1]

The adjugate[2] has sometimes been called the "adjoint",[3] but today the "adjoint" of a matrix normally refers to its corresponding adjoint operator, which is its conjugate transpose.

 

 

Definition[edit]

The adjugate of A is the transpose of the cofactor matrix C of A,

{\displaystyle \operatorname {adj} (\mathbf {A} )=\mathbf {C} ^{\mathsf {T}}~.}{\displaystyle \operatorname {adj} (\mathbf {A} )=\mathbf {C} ^{\mathsf {T}}~.}

In more detail, suppose R is a commutative ring and A is an n×n matrix with entries from R.

  • The (i,jminor of A, denoted Mij, is the determinant of the (n − 1)×(n − 1) matrix that results from deleting row i and column j of A.
  • The cofactor matrix of A is the n×n matrix C whose (ij) entry is the (ijcofactor of A,
{\displaystyle \mathbf {C} _{ij}=(-1)^{i+j}\mathbf {M} _{ij}~.}{\displaystyle \mathbf {C} _{ij}=(-1)^{i+j}\mathbf {M} _{ij}~.}
  • The adjugate of A is the transpose of C, that is, the n×n matrix whose (i,j) entry is the (j,i) cofactor of A,
{\displaystyle \operatorname {adj} (\mathbf {A} )_{ij}=\mathbf {C} _{ji}=(-1)^{i+j}\mathbf {M} _{ji}\,}{\displaystyle \operatorname {adj} (\mathbf {A} )_{ij}=\mathbf {C} _{ji}=(-1)^{i+j}\mathbf {M} _{ji}\,}.

The adjugate is defined as it is so that the product of A with its adjugate yields a diagonal matrix whose diagonal entries are det(A),

{\displaystyle \mathbf {A} \operatorname {adj} (\mathbf {A} )=\det(\mathbf {A} )\,\mathbf {I} ~.}{\displaystyle \mathbf {A} \operatorname {adj} (\mathbf {A} )=\det(\mathbf {A} )\,\mathbf {I} ~.}

A is invertible if and only if det(A) is an invertible element of R, and in that case the equation above yields

{\displaystyle \operatorname {adj} (\mathbf {A} )=\det(\mathbf {A} )\mathbf {A} ^{-1}~,}{\displaystyle \operatorname {adj} (\mathbf {A} )=\det(\mathbf {A} )\mathbf {A} ^{-1}~,}
{\displaystyle \mathbf {A} ^{-1}={\frac {1}{\det(\mathbf {A} )}}\operatorname {adj} (\mathbf {A} )~.}{\displaystyle \mathbf {A} ^{-1}={\frac {1}{\det(\mathbf {A} )}}\operatorname {adj} (\mathbf {A} )~.}

posted on 2017-09-07 11:36  fanbird2008  阅读(656)  评论(0)    收藏  举报

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