【动态规划】bzoj3992 [Sdoi2015]序列统计 10分
#include<cstdio>
using namespace std;
#define MOD 1004535809
int a[8001],f[1001][101],n,m,x,S;
int main()
{
scanf("%d%d%d%d",&n,&m,&x,&S);
for(int i=1;i<=S;++i)
{
scanf("%d",&a[i]);
a[i]%=m;
++f[1][a[i]];
}
for(int i=1;i<n;++i)
for(int j=0;j<m;++j)
for(int k=1;k<=S;++k)
f[i+1][j*a[k]%m]=(f[i+1][j*a[k]%m]+f[i][j])%MOD;
printf("%d\n",f[n][x]);
return 0;
}
——The Solution By AutSky_JadeK From UESTC
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