随笔分类 - Permutation
摘要:Base on next permutation:
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摘要:public class Solution { public List> permuteUnique(int[] nums) { List> ret=new ArrayList>(); Arrays.sort(nums); boolean[] used=new boolean[nums.length]; permute(ne...
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摘要:public class Solution { public List> permute(int[] nums) { List> ret=new ArrayList>(); permute(new ArrayList(),ret,nums); return ret; } private void permute(List l...
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摘要:class Solution { public void nextPermutation(int[] nums) { int i=nums.length-1; while(i>0&&nums[i-1]>=nums[i])i--; if(i==0) { Arrays.sort(nums); ...
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