二分法查找*似*方根

x = 25

epsilon = 0.01

numguess = 0

low = 0.0

high = max(1.0,x)

ans = (high + low )/2

while abs(ans**2 -x ) >=epsilon:

　　numguess +=1

　　if ans**2 < x:

　　　　low = ans

　　else:

　　　　high = ans

　　ans = (high + low )/2.0

print(ans, 'is close to square root of ', x )