python 全站开发 5(59课)

while  3  小游戏 猜数字

要求错误3次推出游戏

代码实现

age_of_ocdboy = 50

i = 0

while    True:

  if   i  = = 3

    break

  guess_age = = int("guess age:")

  if    guess_age = = age_of_ocdboy:

    print("ok")

  elif   guess_age > age_of_ocdboy

    print("wangdacai")

 

  else:

    print("wangxiaocai")

  i += 1

else:

  print("likai")

posted @ 2018-05-23 15:02  mii911  阅读(133)  评论(0)    收藏  举报