WinForm(C#)倒计时(年月日时分秒)

一个朋友提到这个问题,就随手写了一个,本以为很容易,却写了差不多半个小时,关键是年月的判断,现把代码贴出来供需要的朋友参考,也希望能看到大家的计算方法,先在WinForm窗体上放一个label控件(ID为lblShow) 和一个Timer控件(ID为timerMain),后台代码如下:

    public partial class FormTime : Form
    {
        
public FormTime()
        {
            InitializeComponent();
        }

        
private void FormTime_Load(object sender, EventArgs e)
        {
            timerMain.Enabled 
= true;
            timerMain.Interval 
= 1000;
            timerMain.Start();
        }

        
private void timerMain_Tick(object sender, EventArgs e)
        {
            DateTime observeTime 
= DateTime.Parse("2023-11-22 22:45:30");//倒计时日期
            DateTime now = DateTime.Now;    //当前时间
            TimeSpan ts = observeTime.Subtract(now);    //两个时间之差
            StringBuilder result=new StringBuilder();   //存放结果
            int year=observeTime.Year - now.Year;       //得到相差的年
            int month = observeTime.Month - now.Month;  //得到相差的月
            int day = observeTime.Day - now.Day;        //得到相差的日

            
int hmh=(observeTime.Hour-now.Hour)*3600+(observeTime.Minute-now.Minute)*60+(observeTime.Second-now.Second);

            
//如果时分秒比现在的时间晚
            if(hmh<=0)
            {
                
//向日借一
                day--;
                
if((day<=0&&month>0)||(day<=0&&year>0))
                {
                    
//如果天数小于0向月借一
                    day=GetDay(now.Year, now.Month)- now.Day + observeTime.Day;
                    month
--;
                    
if(month<0&&year>0)
                    {
                        
//如果月数小于0,向年借一,同时把月专为正数
                        month += 12;
                        year
--;
                    }
                }
            }


            
//如果天数小于0向月借一
            if ((day < 0 && month > 0|| (day < 0 && year > 0))
            {
                day 
= GetDay(now.Year, now.Month) - now.Day + observeTime.Day;
                month
--;
                
if (month < 0 && year > 0)
                {
                    
//如果月数小于0,向年借一,同时把月专为正数
                    month += 12;
                    year
--;
                }
            }

            
//如果月数小于0,向年借一,同时把月专为正数
            if (month < 0 && year > 0)
            {
                month 
+= 12;
                year
--;
            }

            
if (year<0||(year == 0 && month < 0)||(year == 0 && month==0&&day<0))
            {
                lblShow.Text 
= "已超过日期";
                
return;
            }

            
if (year> 0)
            {
                result.Append(year
+ "");
            }
            
if (month> 0)
            {
                result.Append(month
+ "");
            }
            
if (day> 0)
            {
                result.Append(day
+ "");
            }
            
if (ts.Hours > 0)
            {
                result.Append(ts.Hours 
+ "");
            }
            
if (ts.Minutes > 0)
            {
                result.Append(ts.Minutes 
+ "");
            }
            
if (ts.Seconds > 0)
            {
                result.Append(ts.Seconds 
+ "");
            }
            
if(result.Length==0)
            {
                result.Append(
"已超过日期");
            }
            lblShow.Text 
= result.ToString();
        }

        
//输入月份后获得该月天数
        private int GetDay(int year, int month)
        {
            
int result = 31;
            
switch (month)                           
            {
                
case 4:
                
case 6:
                
case 9:
                
case 11:
                    result 
= 30;
                    
break;
                
case 2:
                    
if ((year % 100 != 0&& (year% 4 == 0|| (year% 400 == 0))
                    {
                        result 
= 29;
                    }
                    
else
                    {
                        result 
= 28;
                    }
                    
break;
            }
            
return result;
        }
    }

 

 效果图:

 

posted @ 2010-11-22 22:52  artwl  阅读(9286)  评论(3编辑  收藏  举报

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