图形类题目

1 - 直角三角形

Problem:

直角三角形

思路

用pow平方的方法，避免开平方的精度损失

Code

#include<iostream>
#include<cmath>
using namespace std;
class CTriangle{
    public :
        //无参构造
        CTriangle() {}
        //有参构造
        CTriangle(int x0,int y0,int x1,int y1,int x2,int y2) : x0(x0), y0(y0), x1(x1), y1(y1), x2(x2), y2(y2) {}
        //方法
        void isYN(){
            //分别预测第三边
            a = pow(x1 - x0, 2) + pow(y1 - y0, 2);
            b = pow(x2 - x0, 2) + pow(y2 - y0, 2);
            c = pow(x2 - x1, 2) + pow(y2 - y1, 2);
            if(a + b == c || a + c == b || c + b == a){
                cout << "Yes" << endl;
            }
            else {
                cout << "No" << endl;
            }
        }
        void len() {
            printf("%.2lf\n", sqrt(a) + sqrt(b) + sqrt(c));
        }
    private:
        int x0;
        int y0;
        int x1;
        int y1;
        int x2;
        int y2;
        double a;
        double b;
        double c;
};
int main(){
    int n;
    cin >> n;
    while(n --){
        int x0, y0, x1, y1, x2, y2;
        cin >> x0 >> y0 >> x1 >> y1 >> x2 >> y2;
        CTriangle ct(x0, y0, x1, y1, x2, y2);
        ct.isYN();
        ct.len();
    }
    return 0;
}