Redshift

查看size

SELECT name AS table_name, ROUND((COUNT(*) / 1024.0),2) as "Size in Gigabytes"
FROM stv_blocklist
INNER JOIN
(SELECT DISTINCT id, name FROM stv_tbl_perm) names
ON names.id = stv_blocklist.tbl
GROUP BY name
ORDER BY "Size in Gigabytes" DESC;