Codeforces Round #274 (Div. 2)-A. Expression

http://codeforces.com/contest/479/problem/A

 

A. Expression

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers a, b, c on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:

• 1+2*3=7
• 1*(2+3)=5
• 1*2*3=6
• (1+2)*3=9

Note that you can insert operation signs only between a and b, and between b and c, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.

It's easy to see that the maximum value that you can obtain is 9.

Your task is: given a, b and c print the maximum value that you can get.

Input

The input contains three integers a, b and c, each on a single line (1 ≤ a, b, c ≤ 10).

Output

Print the maximum value of the expression that you can obtain.

Sample test(s)

input

1
2
3

output

9

input

2
10
3

output

60

 

 

解题思路：求出a,b,c之间加上+或者*号之后表达式的最大值，可以加上括号，所以直接暴力

 

 1 #include<stdio.h>
 2 
 3 int main()
 4 {
 5 
 6     int a,b,c, sum;
 7     int max;
 8     while(scanf("%d%d%d",&a,&b, & c) != EOF){
 9         max = -1;
10         sum = a + b * c;
11         max = max > sum ? max : sum;
12         sum = (a + b) * c;
13         max = max > sum ? max : sum;
14         sum = a * b + c;
15         max = max > sum ? max : sum;
16         sum = a * (b +c);
17         max = max > sum ? max : sum;
18         sum = a + b + c;
19         max = max > sum ? max : sum;
20         sum = a * b * c;
21         max = max > sum ? max : sum;
22         printf("%d\n", max);
23     }
24     return 0;

25 }