public class Demo4ABA {
private static AtomicInteger ai = new AtomicInteger(100);
private static AtomicStampedReference air = new AtomicStampedReference(100, 1);
//ABA问题演示:
//1. 线程1先对数据进行修改 A-B-A过程
//2. 线程2也对数据进行修改 A-C的过程
public static void main(String[] args) throws InterruptedException {
// AtomicInteger可以看到不会有任何限制随便改
// 线程2修改的时候也不可能知道要A-C 的时候,A是原来的A还是修改之后的A
Thread at1 = new Thread(new Runnable() {
public void run() {
ai.compareAndSet(100, 110);
ai.compareAndSet(110, 100);
}
});
Thread at2 = new Thread(new Runnable() {
public void run() {
try {
//为了让线程1先执行完,等一会
TimeUnit.MILLISECONDS.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("AtomicInteger:" + ai.compareAndSet(100, 120));
System.out.println("执行结果:" + ai.get());
}
});
at1.start();
at2.start();
//顺序执行,AtomicInteger案例先执行
at1.join();
at2.join();
//AtomicStampedReference可以看到每次修改都需要设置标识Stamp,相当于进行了1A-2B-3A的操作
//线程2进行操作的时候,虽然数值都一样,但是可以根据标识很容易的知道A是以前的1A,还是现在的3A
Thread tsf1 = new Thread(new Runnable() {
public void run() {
try {
TimeUnit.MILLISECONDS.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
// 预期引用:100,更新后的引用:110,预期标识getStamp() 更新后的标识getStamp() + 1
air.compareAndSet(100, 110, air.getStamp(), air.getStamp() + 1);
air.compareAndSet(110, 100, air.getStamp(), air.getStamp() + 1);
}
});
Thread tsf2 = new Thread(new Runnable() {
public void run() {
//tsf2先获取stamp,导致预期时间戳不一致
int stamp = air.getStamp();
try {
TimeUnit.MILLISECONDS.sleep(100); //线程tsf1执行完
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("AtomicStampedReference:" + air.compareAndSet(100, 120, stamp, stamp + 1));
int[] stampArr = {stamp + 1};
System.out.println("执行结果:" + air.get(stampArr));
}
});
tsf1.start();
tsf2.start();
}
}