python 使用set对列表去重,并保持列表原来顺序

# python 使用set对列表去重,并保持列表原来顺序
list1 = ['cc', 'bbbb', 'afa', 'sss', 'bbbb', 'cc', 'shafa']
for item in list1:
    print('word: %6s  index: %2s' % (item, list1.index(item)))

print('==========================')
list2 = list(set(list1))
list2.sort(key=list1.index)
print(list1)
print(list2)

  运行结果:

 
 

 

def non_repeat_sort(list1):
    list2 = sorted(list(set(list1)), key=lambda e: list1.index(e), reverse=False)
    return list2


def join_list_non_repeat_sort(list1, list2):
    list3 = list1 + list2
    list4 = non_repeat_sort(list3)
    return list4


if __name__ == '__main__':
    list1 = ['a', 'b', 'c', 'a', 'c', 'c']
    list2 = ['c', 'a', 'e', 'f', 'e', 'e']

    print('list1: %s ' % list1)
    print('list2: %s ' % list2)

    list11 = non_repeat_sort(list1)
    list22 = non_repeat_sort(list2)
    print('list11: %s ' % list11)
    print('list22: %s ' % list22)

    result_list = join_list_non_repeat_sort(list1, list2)
    # result_list = join_list_non_repeat_sort(list11, list22)
    print('result_list: %s ' % result_list)

  输出结果:

 

posted @ 2017-12-19 18:17  安迪9468  阅读(792)  评论(0编辑  收藏  举报