华为软件编程题：选秀节目打分 

  1 /* cal_score.cpp
  2  * 选秀节目打分，分为专家评委和大众评委，
  3  * score[] 数组里面存储每个评委打的分数，
  4  * judge_type[] 里存储与 score[] 数组对应的评委类别，
  5  * judge_type[i] == 1，表示专家评委，
  6  * judge_type[i] == 2，表示大众评委，n表示评委总数。
  7  * 打分规则如下：专家评委和大众评委的分数先分别取一个平均分（平均分取整），
  8  * 然后，总分 = 专家评委平均分  * 0.6 + 大众评委 * 0.4，总分取整。
  9  * 如果没有大众评委，则 总分 = 专家评委平均分，总分取整。函数最终返回选手得分。
 10  */
 11 
 12 #include <stdio.h>
 13 
 14 #define N 5
 15 
 16 int cal_score(int score[], int judge_type[], int n)
 17 {
 18     int expert = 0; //专家评委的总分
 19     int general = 0; //大众评委的总分
 20     int total = 0; 
 21     int i = 0; 
 22     int number = 0; 
 23 
 24     for (i = 0; i < n; i++)
 25     {
 26         if (judge_type[i] == 1)
 27         {
 28             expert += score[i]; 
 29             number++; 
 30         }
 31         else 
 32         {
 33             general += score[i]; 
 34         }
 35     }
 36 
 37     if (number == n)
 38     {
 39         total = (int)(expert / n); 
 40     }
 41     else 
 42     {
 43         expert = (int)(expert / n); 
 44         general = (int)(general / n) ; 
 45         total = (int)(0.6 * expert + 0.4 * general); 
 46     }
 47 
 48     return total; 
 49 }
 50 
 51 int main()
 52 {
 53     int score[N]; 
 54     int judge_type[N]; 
 55     int i = 0; 
 56     int total = 0; 
 57 
 58     for (i = 0; i < N; i++)
 59     {
 60         printf("Please input the score %d and the judge type:", i + 1); 
 61         scanf("%d%d", &score[i], &judge_type[i]); 
 62         if ((score[i] < 0) || (score[i] > 100) || (judge_type[i] < 1) || (judge_type[i] > 2))
 63         {
 64             printf("Input error!\n"); 
 65             return 0; 
 66         }
 67     }
 68 
 69     total = cal_score(score, judge_type, N); 
 70     printf("The total score is %d!\n", total);
 71     return 0; 
 72 }
 73 
 74 
 75 //以上为自己写的
 76 //下面为网上的答案
 77 
 78 //#include <stdio.h>
 79 //#include <string.h>
 80 //#include <iostream>
 81 //#include <conio.h>
 82 //#define N 5
 83 //
 84 //int cal_score(int score[], int judge_type[], int n)
 85 //{
 86 //    int expert = 0; 
 87 //    int dazhong = 0; 
 88 //    int zongfen = 0; 
 89 //    int i; 
 90 //    int number = 0; 
 91 //
 92 //    for (i = 0; i < N; i++)
 93 //    {
 94 //        if (judge_type[i] == 1)
 95 //        {
 96 //            expert = expert + score[i]; 
 97 //            number++; 
 98 //        }
 99 //        else dazhong = dazhong + score[i]; 
100 //    }
101 //    if (number == N)
102 //    {
103 //        zongfen = (int)(expert / N); 
104 //    }
105 //    else 
106 //    {
107 //        expert = (int)(expert / N); 
108 //        dazhong = (int)(dazhong / N); 
109 //        zongfen = (int)(0.6 * expert + 0.4 * dazhong); 
110 //    }
111 //    return zongfen; 
112 //}
113 //
114 //int main()
115 //{
116 //    int score[N]; 
117 //    int judge_type[N]; 
118 //    int numberlast = 0; 
119 //    int i; 
120 //    printf("please input the %d score:\n", N); 
121 //    for (i = 0; i < N; i++)
122 //    {
123 //        scanf("%d", &score[i]); 
124 //    }
125 //
126 //    printf("please input the level(1:expert, 2:dazhong)\n"); 
127 //    for (i = 0; i < N; i++)
128 //    {
129 //        scanf("%d", &judge_type[i]); 
130 //    }
131 //    numberlast = cal_score(score, judge_type, N); 
132 //    printf("the last score is %d\n", numberlast); 
133 //    return 0; 
134 //}

 

posted @ 2013-09-07 19:15  安迪Lee  阅读(665)  评论(2)    收藏  举报