B站【狂神说Java】Java零基础学习视频通俗易懂 P50 计算器

写一个计算器,要求实现加减乘除功能,并且能够循环接收新的数据,通过用户交互实现

思路推荐:

  1. 写四个方法:加减乘除
  2. 利用循环 + switch进行用户交互
  3. 传递需要操作的两个数
  4. 输出结果

我的代码如下:

package com.heshian.method;

import java.util.Scanner;

public class CalculatorDemo {
    
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
    
        while (true) {
            System.out.println("欢迎使用计算器,输入\"q\"继续,输入\"#\"退出");
            char choice = scanner.next().charAt(0);
            if (choice == 'q') {
                System.out.println("请输入(用空格隔开):");
    
                double num1 = scanner.nextDouble();
                String operator = scanner.next();
                double num2 = scanner.nextDouble();
    
                switch (operator) {
                    case "+":
                        System.out.println(num1 + " + " + num2  + " = " + add(num1, num2));
                        break;
                    case "-":
                        System.out.println(num1 + " - " + num2  + " = " + minus(num1, num2));
                        break;
                    case "*":
                        System.out.println(num1 + " x " + num2  + " = " + mul(num1, num2));
                        break;
                    case "/":
                        System.out.println(num1 + " / " + num2  + " = " + rid(num1, num2));
                        break;
                }
            } else if (choice == '#') {
                break;
            }
        }
        scanner.close();
    }
    
    //加
    public static double add(double num1, double num2) {
        return num1 + num2;
    }
    
    //减
    public static double minus(double num1, double num2) {
        return num1 - num2;
    }
    
    //乘
    public static double mul(double num1, double num2) {
        return num1 * num2;
    }
    
    //除
    public static double rid(double num1, double num2) {
        return num1 / num2;
    }
}

posted @ 2022-08-04 10:43  hsa2001  阅读(54)  评论(0)    收藏  举报