Max Consecutive Ones

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

 

Note:

• The input array will only contain 0 and 1.
• The length of input array is a positive integer and will not exceed 10,000

 

public class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        int preMax = -1, currentMax = 0;
        for (int num : nums) {
            if (num == 1) currentMax++;
            else {
                preMax = Math.max(preMax, currentMax);
                currentMax = 0;
            }
        }
        return Math.max(preMax, currentMax);
    }
}