Simplify Path

Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

click to show corner cases.

Corner Cases:

 

• Did you consider the case where path = "/../"?
  In this case, you should return "/".
• Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
  In this case, you should ignore redundant slashes and return "/home/foo".

 

Runtime: 6ms

class Solution {
public:
    string simplifyPath(string path) {
        string newPath;
        vector<string> directory;
        stringstream newString(path);
        string temp;
        while (getline(newString, temp, '/')) {
            if (temp == "." || temp == "") continue;
            else if (temp == ".." && !directory.empty()) directory.pop_back();
            else if (temp != "..") directory.push_back(temp);
        }
        
        for (string current : directory) {
            newPath += "/" + current;
        }
        return newPath.empty() ? "/" : newPath;
    }
};