集合练习

随机产生2组10个数字列表

每个数字取值 [10 ,20 ]

统计20个数字中一共有多少个不同数字？

2组之间，不重复的数字有几个，分别是什么？

2组直接进行比较，重复的数字有几个？分别是什么？

 

import random

s1 =  set([random.randint(10,20) for _ in range(10)]) 
s2 =  set([random.randint(10,20) for _ in range(10)])

print(s1,s2)

a = s1 | s2  
a1 = s1.union(s2) #使用函数名

print(a,a1)

b = s1 ^ s2  
b1 = s1.symmetric_difference(s2) #使用函数名

print(b,b1) 

c = s1 & s2 
c1 = s1.intersection(s2)  #使用函数名

print(c,c1)

 

import random
lst1 = [None] * 10
lst2 = [None] * 10
for i in range(10):
    lst1[i] = random.randint(10,20)
    lst2[i] = random.randint(10,20)
print(lst1,lst2)

s1 = set(lst1)
s2 = set(lst2)

print(s1,s2)


a = s1 | s2  
a1 = s1.union(s2)
print(a,a1)

b = s1 ^ s2  
b1 = s1.symmetric_difference(s2)
print(b,b1)

c = s1 & s2 
c1 = s1.intersection(s2)
print(c,c1)

#也可以使用空列表的方式，往里面追加

lst1 = []
lst2 = []

for i in range(10):
    lst1.append(random.randint(10,20))
    lst2.append(random.randint(10,20))
print(lst1)
print(lst2)

 使用解析式生成随机数

lst1 = [random.randint(10,20) for _ in range(10)]
lst2 = [random.randint(10,20) for _ in range(10)]
print(lst1)
print(lst2)


s1 = set(lst1)
s2 = set(lst2)

print(s1,s2)


a = s1 | s2
a1 = s1.union(s2)
print(a,a1)

b = s1 ^ s2
b1 = s1.symmetric_difference(s2)
print(b,b1)

c = s1 & s2
c1 = s1.intersection(s2)
print(c,c1)